CODEWITHSUNDEEP
python
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Reputation: 2083

How to send calling class name to logger class in Python >

I am new to Python and trying to implement logger in my code. I have created a python file: setup_logger.py

import logging

CLASS_NAME = ''

# Create and configure logger
LOG_FORMAT = '%(asctime)s - %(name)s - %(levelname)s - %(message)s'
logging.basicConfig(filename='/Users/bobby/Desktop/lumberjack.log', level=logging.DEBUG, format=LOG_FORMAT)
logger = logging.getLogger()

I am using this logger configuration in another python file: GetLogger.py as below

from LoggerLevels.setup_logger import logger

if __name__ == '__main__':
    logger.error('This is a basic log error message')
    logger.info('This is a warning message')

The log is being printed in the file as:

2020-06-17 14:54:47,161 - root - ERROR - This is a basic log error message
2020-06-17 14:54:47,161 - root - INFO - This is a warning message

But I see the class name is printed as root. I understand that it is coming due to the setting in setup_logger.py file. Is there anyway I can send the current class name that is logging messages into my file ? For ex: I am using the logger object from GetLogger.py file. Is there anyway I can log the message as

2020-06-17 14:54:47,161 - GetLogger - ERROR - This is a basic log error message
2020-06-17 14:54:47,161 - GetLogger - INFO - This is a warning message

Could anyone let me know how can I achieve that ?

Upvotes: 4

Views: 5478

Answers (2)

j32u4ukh
j32u4ukh

Reputation: 19

Here is a advice for you to take it as a reference.

logger_format = '%(asctime)s [%(className)s] %(funcName)s | %(message)s (%(name)s)'
extra_dict = {'className': 'NameOfClass'}
logger = logging.getLogger('logger_name')

def callLogger():
    logger.debug('log message', extra=extra_dict)

callLogger()

And result would be like:

2021-02-21 17:08:34,066 [NameOfClass] callLogger | log message (logger_name)

When we use the same logger in different class, this way is also work.

If you use different logger in each class, you have easier way like:

# put the (%(name)s) to position of name of class
logger_format = '%(asctime)s [%(name)s] %(funcName)s | %(message)s'

# name the logger name as class name
logger = logging.getLogger('NameOfClass')

def callLogger():
    logger.debug('log message')

callLogger()

And result would be like:

2021-02-21 17:08:34,066 [NameOfClass] callLogger | log message

Refer to Python official document

Upvotes: 1

sanitizedUser
sanitizedUser

Reputation: 2115

Use:

LOG_FORMAT = '%(asctime)s - %(module)s - %(levelname)s - %(message)s'

If that doesn't work for you, you can try %(filename)s or create a custom class with setLoggerClass method.

Upvotes: 5

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