CODEWITHSUNDEEP
pythonpandas
Doggy Face
Doggy Face

Reputation: 429

Determine the difference between time

I have a dataframe that consists of date and time column like showed below, with the date format (MM/DD/YYYY);

|Date    | Time   |
|--------|--------|
|1/1/2019|1200hrs |
|1/1/2019|1300hrs |
|1/1/2019|1400hrs |
|1/2/2019|1200hrs |
|1/2/2019|1300hrs |
|1/2/2019|1400hrs |
|1/2/2019|1700hrs |

I want to generate another column that shows the difference between each time like the dataframe shown below,

|Date    | Time   |Time difference(mins)|
|--------|--------|---------------------|
|1/1/2019|1200hrs |-                    |
|1/1/2019|1300hrs |60                   |
|1/1/2019|1400hrs |60                   |
|1/2/2019|1200hrs |-                    |
|1/2/2019|1300hrs |60                   |
|1/2/2019|1400hrs |60                   |
|1/2/2019|1700hrs |180                  |

The time difference should be calculated on the same date. Can anyone give me some idea of how to do it? Thank you!

Upvotes: 2

Views: 107

Answers (1)

jezrael
jezrael

Reputation: 863791

Use DataFrameGroupBy.diff with convert to datetimes, last convert timedeltas to seconds by Series.dt.total_seconds and last to minutes by division of 60:

df['Time'] = pd.to_datetime(df['Date'] + df['Time'], format='%m/%d/%Y%H%Mhrs')
df['Time difference(mins)'] = df.groupby('Date')['Time'].diff().dt.total_seconds().div(60)
print (df)
       Date                Time  Time difference(mins)
0  1/1/2019 2019-01-01 12:00:00                    NaN
1  1/1/2019 2019-01-01 13:00:00                   60.0
2  1/1/2019 2019-01-01 14:00:00                   60.0
3  1/2/2019 2019-01-02 12:00:00                    NaN
4  1/2/2019 2019-01-02 13:00:00                   60.0
5  1/2/2019 2019-01-02 14:00:00                   60.0
6  1/2/2019 2019-01-02 17:00:00                  180.0

Upvotes: 3

Related Questions