CODEWITHSUNDEEP
pythonpython-3.xlistsorting
Volodymyr
Volodymyr

Reputation: 57

PYTHON Sort list with empty, string and numeric values

I want to sort short list like:

# we can have only 3 types of value: any string numeric value like '555', 'not found' and '' (can have any variation with these options)
row = ['not found', '', '555']

to

# numeric values first, 'not found' less prioritize and '' in the end
['555', 'not found', '']

I trying use 

row.sort(key=lambda x: str(x).isnumeric() and not bool(x))

but it's not working

How can I sort it? (numeric values first, 'not found' less prioritize and '' in the end)

Upvotes: 0

Views: 915

Answers (4)

Adam Boinet
Adam Boinet

Reputation: 531

This will sort your list and give 'not found' a higher priority than '':

l = [int(a) for a in row if a.isnumeric()] # Or float(a)
l.sort()
row = [str(a) for a in l] +\
    ['not found'] * row.count('not found') +\
    [''] * row.count('')

Upvotes: 0

Teja
Teja

Reputation: 325

Edit: Sorting non numeric values per ask

ar = [i for i in row if not i.isnumeric()]
ar.sort(reverse=True)
row = [i for i in row if i.isnumeric()] + ar

Upvotes: 1

EdKenbers
EdKenbers

Reputation: 117

This will do the trick too:

row = ['not found', '', 555, 1, '5' , 444]
print(row)

def func(x):
    if str(x).isnumeric():
        return  1/-int(x) # ordering numerics event if they are strings 
    elif str(x) == 'not found':
        return  2
    elif str(x) == '':
        return  3

row2 = row.sort(key=func)

print(row)

Results:

['not found', '', 555, 1, '5', 444]
[1, '5', 444, 555, 'not found', '']

Upvotes: 0

Nikhil Ghule
Nikhil Ghule

Reputation: 124

def custom_sort(list):
    L1 = []
    L2 = []
    L3 = []
    for element in list:
        if element.isnumeric():
            L1.append(element)
        if element == 'Not found':
            L2.append(element)
        else : L3.append(element)
    L1.sort()
    L1.append(L2).append(L3)
    return L1

Upvotes: 1

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