Robin Singh
Robin Singh

Reputation: 1796

How to solve Avoided redundant navigation to current location error in vue?

I am new in vue and i got the error after user logged in and redirect to another route. Basically i am a PHP developer and i use laravel with vue. Please help me to solve this error.

Uncaught (in promise) Error: Avoided redundant navigation to current location: "/admin".

Here is the screenshot too

enter image description here

Vue Code

 methods: {
        loginUser() {
            var data = {
                email: this.userData.email,
                password: this.userData.password
            };
            this.app.req.post("api/auth/authenticate", data).then(res => {
                const token = res.data.token;
                sessionStorage.setItem("chatbot_token", token);
                this.$router.push("/admin");
            });
        }
    }

Vue Routes

const routes = [
    {
        path: "/admin",
        component: Navbar,
        name: "navbar",
        meta: {
            authGuard: true
        },
        children: [
            {
                path: "",
                component: Dashboard,
                name: "dashboard"
            },
            {
                path: "users",
                component: Users,
                name: "user"
            }
        ]
    },
    {
        path: "/login",
        component: Login,
        name: "login"
    }
];

const router = new VueRouter({
    routes,
    mode: "history"
});

router.beforeEach((to, from, next) => {
    const loggedInUserDetail = !!sessionStorage.getItem("chatbot_token");
    if (to.matched.some(m => m.meta.authGuard) && !loggedInUserDetail)
        next({ name: "login" });
    else next();
});

Upvotes: 83

Views: 129680

Answers (20)

Ḿichael
Ḿichael

Reputation: 9

You can use pointer-events to disable the active link.

.router-link-exact-active {
    pointer-events: none;
}

Upvotes: 0

pirs
pirs

Reputation: 2463

Global solution

In router/index.js, after initialization


// init or import router..


/* ... your routes ... */


// error handler
const onError = (e) => {
  // avoid NavigationDuplicated
  if (e.name !== 'NavigationDuplicated') throw e
}

// keep original function
const _push = router.__proto__.push
// then override it
router.__proto__.push = function push (...args) {
  try {
    const op = _push.call(this, ...args)
    if (op instanceof Promise) op.catch(onError)
    return op
  } catch (e) {   
    onError(e)
  }
}

Upvotes: 3

rgb
rgb

Reputation: 1294

I don't understand why they no longer handle this case internally, but this is what I have implemented in our app.

If you are already on the fullPath then dont bother pushing / replacing

const origPush = Router.prototype.push;
Router.prototype.push = function(to) {
  const match = this.matcher.match(to);
  // console.log(match.fullPath, match)
  if (match.fullPath !== this.currentRoute.fullPath) {
    origPush.call(this, to);
  } else {
    // console.log('Already at route', match.fullPath);
  }
}

const origReplace = Router.prototype.replace;
Router.prototype.replace = function(to) {
  const match = this.matcher.match(to);
  // console.log(match.fullPath, match)
  if (match.fullPath !== this.currentRoute.fullPath) {
    origReplace.call(this, to);
  } else {
    // console.log('Already at route', match.fullPath);
  }
}

Upvotes: 1

Olivier de Jonge
Olivier de Jonge

Reputation: 1504

In addition to the above mentioned solutions: a convenient way is to put this snippet in main.js to make it a global function


Vue.mixin({
    /**
     * Avoids redundand error when navigating to already active page
     */
    routerPush(route) {
      this.$router.push(route).catch((error) => {
        if(error.name != "NavigationDuplicated") {
          throw error;
        }
      })
    },
})

Now you can call in any component:

this.routerPush('/myRoute') 

Upvotes: 2

lordh
lordh

Reputation: 21

Clean solution ;)

Move the code to an util function. So you can replace all this.$router.push with it.

import router from '../router'; // path to the file where you defined 
                                // your router

const goToRoute = (path) => 
    if(router.currentRoute.fullPath !== path) router.push(path);

export {
    goToRoute
}

Upvotes: 2

Davron Achilov
Davron Achilov

Reputation: 621

  1. For components <router-link> You can create a new component instead of <router-link>.

Component name: <to-link>

<template>
  <router-link :to="to" :event="to === $route.path || loading ? '' : 'click'" :class="classNames">
    <slot></slot>
  </router-link>
</template>

<script>
export default {
  name: 'ToLink',
  props: {
    to: {
      type: [String, Number],
      default: ''
    },
    classNames: {
      type: String,
      default: ''
    },
    loading: {
      type: Boolean,
      default: false
    }
  }
}
</script>

For bind:

import ToLink from '@/components/to-link'
Vue.component('to-link', ToLink)
  1. For $router.push() need create global method.
toHttpParams(obj) {
    let str = ''
    for (const key in obj) {
      if (str !== '') {
        str += '&'
      }
      str += key + '=' + encodeURIComponent(obj[key])
    }
    return str
  },
  async routerPush(path, queryParams = undefined, params = undefined, locale = true) {
    let fullPath = this.$route.fullPath
    if (!path) {
      path = this.$route.path
    }
    if (!params) {
      params = this.$route.params
    }
    if (queryParams && typeof queryParams === 'object' && Object.entries(queryParams).length) {
      path = path + '?' + this.toHttpParams(queryParams)
    }
   
    if (path !== fullPath) {
      const route = { path, params, query: queryParams }
      await this.$router.push(route)
    }
  }

Upvotes: 0

Sudarsan
Sudarsan

Reputation: 107

Late to the party, but trying to add my 10 cents. Most of the answers- including the one which is accepted are trying to hide the exception without finding the root cause which causes the error. I did have the same issue in our project and had a feeling it's something to do with Vue/ Vue router. In the end I managed to prove myself wrong and it was due to a code segment we had in App.vue to replace the route in addition to the similar logic like you in the index.ts.

this.$router.replace({ name: 'Login' })

So try to do a search and find if you are having any code which calls $router.replace OR $router.push for the route you are worried about- "/admin". Simply your code must be calling the route more than once, not the Vue magically trying to call it more than once.

Upvotes: 1

Jackaroo Ng
Jackaroo Ng

Reputation: 655

I found the solution by adding the following code to router.js:

import router from 'vue-router'; 

const originalPush = router.prototype.push
router.prototype.push = function push(location) {
  return originalPush.call(this, location).catch(err => err)
}

Upvotes: 11

Gkiokan
Gkiokan

Reputation: 3620

Just to make this complete you can also compare the from and to route fullPaths and compare them against each other which seems to me a simple, valid and reusable solution.

Here is an example in a component method:

 move(params){
    // get comparable fullPaths
    let from  = this.$route.fullPath
    let to    = this.$router.resolve(params).route.fullPath

    if(from === to) { 
        // handle any error due the redundant navigation here
        // or handle any other param modification and route afterwards
        return 
    }

    // route as expected
    this.$router.push(params)
}

If you wanna use that you just put your route params in it like this.move({ name: 'something' }). This is the easiest way to handle the duplicate route without running into try catch syntax. And also you can have that method exported in Vue.prorotype.$move = ... which will work across the whole application.

Upvotes: 13

Quang Dong
Quang Dong

Reputation: 497

Short solution:

  if (this.$router.currentRoute.name !== 'routeName1') {
    this.$router.push({
      name: 'routeName2',
    })
  }

Upvotes: 1

Saintilien Wilson
Saintilien Wilson

Reputation: 51

I had this problem and i solve it like that.

by adding that in my router file

import Router from 'vue-router'

Vue.use(Router)

const originalPush = Router.prototype.push 
Router.prototype.push = function push(location) {
   return originalPush.call(this, location).catch(err => err)
}

Upvotes: 1

Bryce
Bryce

Reputation: 81

Provide a Typescript solution

The idea is to overwrite the router.push function. You can handle (ignore) the error in one place, instead of writing catch everywhere to handle it.

This is the function to overwrite

export declare class VueRouter {
  // ...
  push(
    location: RawLocation,
    onComplete?: Function,
    onAbort?: ErrorHandler
  ): void
}

Here is the code

// in router/index.ts

import Vue from 'vue';
import VueRouter, { RawLocation, Route } from 'vue-router';

Vue.use(VueRouter);

const originalPush = VueRouter.prototype.push;
VueRouter.prototype.push = function push(location: RawLocation): Promise<Route> {
  return new Promise((resolve, reject) => {
    originalPush.call(this, location, () => {
      // on complete

      resolve(this.currentRoute);
    }, (error) => {
      // on abort

      // only ignore NavigationDuplicated error
      if (error.name === 'NavigationDuplicated') {
        resolve(this.currentRoute);
      } else {
        reject(error);
      }
    });
  });
};

// your router configs ...

Upvotes: 8

Umair Ahmed
Umair Ahmed

Reputation: 8787

I have experienced the same issue and when I looked for a solution I found .catch(() => {}) which is actually telling the browser that we have handled the error please don’t print the error in dev tools :) Hehehe Nice hack! but ignoring an error is not a solution I think. So what I did, I created a utility function that takes two parameters router, path, and compares it with the current route's path if both are the same it means we already on that route and it ignore the route change. So simple :)

Here is the code.

export function checkCurrentRouteAndRedirect(router, path) {
  const {
    currentRoute: { path: curPath }
  } = router;
  if (curPath !== path) router.push({ path });
}

checkCurrentRouteAndRedirect(this.$router, "/dashboard-1");
checkCurrentRouteAndRedirect(this.$router, "/dashboard-2");

Upvotes: 1

ilgam
ilgam

Reputation: 4450

It means - you want to navigate to a route that looks the same as the current one and Vue doesn’t want to trigger everything again.

 methods: {
    loginUser() {
        var data = {
            email: this.userData.email,
            password: this.userData.password
        };
        this.app.req.post("api/auth/authenticate", data).then(res => {
            const token = res.data.token;
            sessionStorage.setItem("chatbot_token", token);
            // Here you conditioally navigate to admin page to prevent error raised
            if(this.$route.name !== "/admin") {
              this.$router.push("/admin");
            }
            
        });
    }
}

Upvotes: 2

J. Liu
J. Liu

Reputation: 366

you can define and use a function like this:

routerPush(path) {
  if (this.$route.path !== path) {
    this.$router.push(path);
  }
}

Upvotes: 5

Frnak
Frnak

Reputation: 6802

I guess this answer comes in super late. Instead of catching the error I looked for a way to prevent the error the come up. Therefore I've enhanced the router by an additional function called pushSave. Probably this can be done via navGuards as well

VueRouter.prototype.pushSave = function(routeObject) {
  let isSameRoute = true

  if (this.currentRoute.name === routeObject.name && routeObject.params) {
    for (const key in routeObject.params) {
      if (
        !this.currentRoute.params[key] ||
        this.currentRoute.params[key] !== routeObject.params[key]
      ) {
        isSameRoute = false
      }
    }
  } else {
    isSameRoute = false
  }

  if (!isSameRoute) {
    this.push(routeObject)
  }
}

const router = new VueRouter({
  routes
})

As you've probably realized this will only work if you provide a routeObject like

this.$router.pushSave({ name: 'MyRoute', params: { id: 1 } })

So you might need to enhance it to work for strings aswell

Upvotes: 0

Yeasir Arafat
Yeasir Arafat

Reputation: 2191

I have added the code below in the main.js file of my project and the error disappeared.

import Router from 'vue-router'
const routerPush = Router.prototype.push
Router.prototype.push = function push(location) {
return routerPush.call(this, location).catch(error => error)
};

Upvotes: 2

Adonis Gaitatzis
Adonis Gaitatzis

Reputation: 3739

Maybe this is happening because your are trying to route to the existing $route.matched.path.

For original-poster

You may want to prevent the error by preventing a route to the same path:

if (this.$route.path != '/admin') {
    this.$router.push("/admin");
}

Generic solutions

You could create a method to check for this if you are sending dynamic routes, using one of several options

  1. Easy: Ignore the error
  2. Hard: Compare the $route.matched against the desired route

1. Ignore the error

You can catch the NavigationDuplicated exception and ignore it.

pushRouteTo(route) {
    try {
        this.$router.push(route);
    } catch (error) {
       if (!(error instanceof NavigationDuplicated)) {
           throw error;
       }
    }
}

Although this is much simpler, it bothers me because it generates an exception.

2. Compare the $route.matched against the desired route

You can compare the $route.matched against the desired route

pushRouteTo(route) {
    // if sending path:
    if (typeof(route) == "string") {
        if (this.$route.path != route) {
            this.$router.push(route);
        }
    } else { // if sending a {name: '', ...}
        if (this.$route.name == route.name) {
            if ('params' in route) {
                let routesMatched = true;
                for (key in this.$route.params) {
                    const value = this.$route.params[key];
                    if (value == null || value == undefined) {
                        if (key in route.params) {
                            if (route.params[key] != undefined && route.params[key] != null) {
                                routesMatched = false;
                                break;
                            }
                        }
                    } else {
                        if (key in route.params) {
                            if (routes.params[key] != value) {
                                routesMatched = false;
                                break
                            }
                        } else {
                            routesMatched = false;
                            break

                        }
                    }
                    if (!routesMatched) {
                        this.$router.push(route);
                    }
                }
            } else {
                if (Object.keys(this.$route.params).length != 0) {
                    this.$router.push(route);
                }
            }
        }
    }
}

This is obviously a lot longer but doesn't throw an error. Choose your poison.

Runnable demo

You can try both implementations in this demo:

const App = {
  methods: {
    goToPageCatchException(route) {
      try {
        this.$router.push(route)
      } catch (error) {
        if (!(error instanceof NavigationDuplicated)) {
          throw error;
        }
      }
    },
    goToPageMatch(route) {
    if (typeof(route) == "string") {
        if (this.$route.path != route) {
            this.$router.push(route);
        }
    } else { // if sending a {name: '', ...}
        if (this.$route.name == route.name) {
            if ('params' in route) {
                let routesMatched = true;
                for (key in this.$route.params) {
                    const value = this.$route.params[key];
                    if (value == null || value == undefined) {
                        if (key in route.params) {
                            if (route.params[key] != undefined && route.params[key] != null) {
                                routesMatched = false;
                                break;
                            }
                        }
                    } else {
                        if (key in route.params) {
                            if (routes.params[key] != value) {
                                routesMatched = false;
                                break
                            }
                        } else {
                            routesMatched = false;
                            break

                        }
                    }
                    if (!routesMatched) {
                        this.$router.push(route);
                    }
                }
            } else {
                if (Object.keys(this.$route.params).length != 0) {
                    this.$router.push(route);
                }
            }
        } else {
          this.$router.push(route);
        }
    }
    },
  },
  template: `
  <div>
    <nav class="navbar bg-light">
          <a href="#" @click.prevent="goToPageCatchException({name:'page1'})">Catch Exception</a>
          <a href="#" @click.prevent="goToPageMatch({name:'page2'})">Match Route</a>
    </nav>
    <router-view></router-view>
  </div>`
}
const Page1 = {template: `
  <div class="container">
    <h1>Catch Exception</h1>
    <p>We used a try/catch to get here</p>
  </div>`
}
const Page2 = {template: `
  <div class="container">
    <h1>Match Route</h1>
    <p>We used a route match to get here</p>
  </div>`
}

const routes = [
  { name: 'page1', path: '/', component: Page1 },
  { name: 'page2', path: '/page2', component: Page2 },
]

const router = new VueRouter({
  routes
})

new Vue({
  router,
  render: h => h(App)
}).$mount('#app')
<link href="https://cdn.jsdelivr.net/npm/[email protected]/dist/css/bootstrap.min.css" rel="stylesheet"/>
<script src="https://cdnjs.cloudflare.com/ajax/libs/vue/2.6.12/vue.min.js"></script>
<script src="https://unpkg.com/vue-router/dist/vue-router.js"></script>

<div id="app"></div>

Upvotes: 36

bartekwaliszko
bartekwaliszko

Reputation: 1162

As I remember well, you can use catch clause after this.$router.push. Then it will look like:

this.$router.push("/admin").catch(()=>{});

This allows you to only avoid the error displaying, because browser thinks the exception was handled.

Upvotes: 91

Luckylooke
Luckylooke

Reputation: 4539

I don't think suppressing all errors from router is good practice, I made just picks of certain errors, like this:

router.push(route).catch(err => {
    // Ignore the vuex err regarding  navigating to the page they are already on.
    if (
      err.name !== 'NavigationDuplicated' &&
      !err.message.includes('Avoided redundant navigation to current location')
    ) {
      // But print any other errors to the console
      logError(err);
    }
  });

Upvotes: 59

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