CODEWITHSUNDEEP
javascriptregexdiscord.js
user9598971
user9598971

Reputation:

Detect whole word at the end without punctuation in discord.js

I want the bot to respond to my message if it contains a specific word, at the end of a sentence or in a message alone, ignoring the punctuation, and will ignore the message if the word sticks another word. Example : the word is "yes"

"I said yes !" -> true

"Yes" -> true

"Eyes" -> false

For the moment, I made this :

const Discord = require('discord.js');
const client = new Discord.Client();

client.once('ready', () => {
    console.log(`Online`);
});

const responseObject = {
    "yes": "ok !",
    "no": "potato !"
};

client.on('message', message => {
    var regex = /[!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~]/g;
    var regexx = /[ \t]+$/g;
    message.content = message.content.toLowerCase();
    message.content = message.content.replace(regex, '')
    message.content = message.content.replace(regexx, '')

    if(responseObject[message.content]) {
        message.channel.send(responseObject[message.content]);
    }

});

And also, is there a way to optimize more this code ? Thanks in advance.

Upvotes: 0

Views: 356

Answers (1)

Aplet123
Aplet123

Reputation: 35540

Here is a function to get the last word in a string:

function getLastWord(str) {
    return (str.toLowerCase().match(/(\w+)\W*$/) || [])[1];
}

getLastWord("I said yes !"); // "yes"
getLastWord("Yes"); // "yes"
getLastWord("Eyes"); // "eyes"

Here's the regex explained:

(\w+) - match any word
\W* - match any non-alphanumeric characters
$ - the end of the string

Basically, requiring every character between the word and the end of the string to be non-alphanumeric forces the word to be the last word in the sentence. the (statement || []) ensures that the function returns undefined when there are no words instead of erroring out. The [1] is to get the first capturing group, since match returns an array.

Upvotes: 3

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