CODEWITHSUNDEEP
pythonpermutation
user11173832
user11173832

Reputation:

how do I get the fixed number of permutation of certain number

let say I have string number with "323123" if I want to get the fixed number n digit permutation of "323123". 

for example if n=3 '323','321'.....'123' <br/>
n=2 then '32',23'.....

Upvotes: 1

Views: 73

Answers (2)

panadestein
panadestein

Reputation: 1291

The desired output (combinations as single strings) can be obtained like this (for the example case n = 2):

import itertools as it 

num = "323123"
n = 2
perms = ["".join(el) for el in it.permutations(list(num), n)]
print(perms)

Which prints:

['32', '33', '31', '32', '33', '23', '23', '21', '22', '23', '33', '32', '31', '32', '33', '13', '12', '13', '12', '13', '23', '22', '23', '21', '23', '33', '32', '33', '31', '32']

Upvotes: 0

Max
Max

Reputation: 126

Try this:

from itertools import permutations

string = "323123"
n = 2

perms = list(permutations(string, n))

Output:

[('3', '2'), ('3', '3'), ('3', '1'), ('3', '2'), ('3', '3'), ('2', '3'), ('2', '3'), ('2', '1'), ('2', '2'), ('2', '3'), ('3', '3'), ('3', '2'), ('3', '1'), ('3', '2'), ('3', '3'), ('1', '3'), ('1', '2'), ('1', '3'), ('1', '2'), ('1', '3'), ('2', '3'), ('2', '2'), ('2', '3'), ('2', '1'), ('2', '3'), ('3', '3'), ('3', '2'), ('3', '3'), ('3', '1'), ('3', '2')]```

Upvotes: 2

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