Reputation: 1381
I am pretty new to python and I am trying to parse email from gmail via python's imaplib and email. It is working pretty well but I am having issues with email attachments.
I would like to parse out all of the plaintext from the email while ignoring any HTML that may be inserted as a secondary content type while also removing and saving all other attachments. I have been trying the following:
...imaplib connection and mailbox selection...
typ, msg_data = c.fetch(num, '(RFC822)')
email_body = msg_data[0][1]
mail = email.message_from_string(email_body)
for part in mail.walk():
if part.get_content_type() == 'text/plain':
body = body + '\n' + part.get_payload()
else:
continue
This was my original attempt to just take the plaintext portions of an email, but when someone sends an email with a text attachment, the contents of the text file shows up for the 'body' variable above.
Can someone tell me how I can extract the plaintext portions of an email while ignoring the secondary HTML that is sometimes present, while also saving all other types of file attachments as files? I appologize if this doesn't make a lot of sense. I will update the question with more clarification if needed.
Upvotes: 12
Views: 9014
Reputation: 5161
If you just need to keep text attachments out of the body
variable with what you have there, it should be as simple as this:
mail = email.message_from_string(email_body)
for part in mail.walk():
c_type = part.get_content_type()
c_disp = part.get('Content-Disposition')
if c_type == 'text/plain' and c_disp == None:
body = body + '\n' + part.get_payload()
else:
continue
Then if the Content-Disposition indicates that it's an attachment, you should be able to use part.get_filename()
and part.get_payload()
to handle the file. I don't know if any of this can vary, but it's basically what I've used in the past to interface with my mail server.
Upvotes: 11