Reputation: 407
I would like to use sympy to solve for a vector that satisfies a set of quadratic and linear equations, such as x.T @ A @ x = x.T @ B @ x = 1
, and x.T @ C = 0
. Here is my attempt:
import numpy as np
from sympy.polys.polymatrix import PolyMatrix
from sympy import symbols
from sympy.solvers import solve_poly_system
x = PolyMatrix([symbols(f'x{k}') for k in range(2)])
A = np.eye(2)
B = np.array([1, 0]).reshape([2, 1])
one = PolyMatrix([1])
solve_poly_system([x.T @ A @ x - one, x.T @ B], [symbols(f'x{k}') for k in range(2)])
However, this generates the following error:
PolynomialError: non-commutative expressions are not supported
Any suggestions?
Upvotes: 1
Views: 197
Reputation: 14480
Just use solve
instead of solve_poly_system
:
>>> solve([x.T @ A @ x - one, x.T @ B], [symbols(f'x{k}') for k in range(2)])
[(0.0, -1.0), (0.0, 1.0)]
Upvotes: 1