Gabriel Nair
Gabriel Nair

Reputation: 11

How to sum the digits of each value in an array to create a new array?

Upvotes: 1

Views: 788

Answers (3)

Trenton McKinney
Trenton McKinney

Reputation: 62373

t = [1555, 1116, 221, 997]

result = [sum(int(d) for d in str(v)) for v in t]

print(result)
[16, 9, 5, 25]
  • Corresponding for-loop
result = list()
for v in t:
    r = list()
    for d in str(v):
        r.append(int(d))
    result.append(sum(r))

%%timeit comparison

  • Given the following test list
import numpy as np

np.random.seed(123)
t = [np.random.randint(100, 4000) for _ in range(4000000)]
  • This answer
%%timeit
[sum(int(d) for d in str(v)) for v in t]

5.27 s ± 60.9 ms per loop (mean ± std. dev. of 7 runs, 1 loop each)
%%timeit
[sum(map(int, list(str(x)))) for x in t]

4.63 s ± 37 ms per loop (mean ± std. dev. of 7 runs, 1 loop each)
def sum_digits(n):
    r = 0
    while n:
        r, n = r + n % 10, n // 10
    return r

%%timeit
[sum_digits(n) for n in t]

1.72 s ± 10.7 ms per loop (mean ± std. dev. of 7 runs, 1 loop each)

Upvotes: 1

Gabio
Gabio

Reputation: 9484

You can use list comprehension where each number is converted to string -> splitted to list of chars -> converted to digits(numbers) back -> summed:

start = [1555, 1116, 221, 997]
end = [sum(map(int, list(str(x)))) for x in start]
print(end) # output: [16, 9, 5, 25]

Upvotes: 1

minerharry
minerharry

Reputation: 111

I believe what you are asking is to create an array whose elements are the sum of the digits of each number in the original array. The number digit summation is shamelessly stolen from Sum the digits of a number - python, and putting it all together you get:

def sum_digits(n):
   r = 0
   while n:
       r, n = r + n % 10, n // 10
   return r

in_array = [1555, 1116, 221, 997]
out_array = [sum_digits(n) for n in in_array]
print(out_array)

Hope this helps!

Upvotes: 1

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