How to configure urls.py in django to redirect to another file's urls?

Question

I'm following a django tutorial that is a little outdated and in the urls.py file of the first app's directory we need to configure where to direct django to for any url starting with 'notes/'. There are two separate 'apps' inside the project. I'm in the first one, not notes.

This is the code currently. I added include to import statement:

from django.contrib import admin
from django.urls import path, include

urlpatterns = [
    path('admin/', admin.site.urls),
    path(url(r’^notes/‘, include('notes.urls'))),
]

Inside the urlpatterns object, on the first line, path('admin/', admin.site.urls), comes predefined, but I need to add a redirect such that django goes to a different app, called 'notes' and searches there for its entry point, since all of the urls will begin with ‘notes/’.

The tutorial says to use a regular expression and uses this code:

url(r’^notes/‘, include(notes.urls))

so that any url that starts with 'notes/' should be redirected to this other file notes.urls.

However the predefined ones that currently come out of the box with a django project start with path. I enclosed my notes/n redirect line in path, but not sure if this is correct. Should I instead directly write:

url(r’^notes/‘, include(notes.urls))

Also, do I need to delete the first line provided?

  path('admin/', admin.site.urls),

The tutorial has:

urlpatterns = patterns('',   
 url(r’^notes/‘, include(notes.urls)),
)

and no admin urls line. It's from 2014 I believe.

Answer 1

Simply do:

path('notes/', include('notes.urls'))