Reputation: 139
So folks, below is a part of my code, I need to sum what’s in each column and sum what’s in the entire table, could you help me on how to do that, using an array in code? just talking didn't help me, I would like to see it in code to understand it better.
void main(void){
//Matrix Declaration and Initialization with the Production Data of each Branch;
//Format: productionXX[shift][week];
int productionSP[3][4] = {{1000, 1030, 900, 990},
{1010, 1045, 1100, 1015},
{1050, 1065, 1075, 1100}};
Upvotes: 1
Views: 216
Reputation: 5766
You could do it using loops as follows -
#include <stdio.h>
int main() {
int productionSP[3][4] = {{1000, 1030, 900, 990},
{1010, 1045, 1100, 1015},
{1050, 1065, 1075, 1100}};
int column_sum[4]={0};
int final_sum=0;
// i denotes iterating over each of the rows
for(int i=0;i<3;i++){
// j denotes iterating over each column of each row
for(int j=0;j<4;j++){
final_sum+=productionSP[i][j];
column_sum[j] += productionSP[i][j];
}
}
printf("column sums - \n");
for(int i=0;i<4;i++){
printf("Column #%d - %d\n",i+1,column_sum[i]);
}
printf("final_sum = %d",final_sum);
}
Output :
column sums -
Column #1 - 3060
Column #2 - 3140
Column #3 - 3075
Column #4 - 3105
final_sum = 12380
You can change the loop break conditions as per your productionSP
array. For now it has static 3 rows and 4 columns. You can change your loop condition accordingly when you matrix is of a different size.
Hope this helps !
Upvotes: 2