hmood
hmood

Reputation: 603

How to print only once inside a while loop in python

I want to print inside a while loop only once. As shown below:

 # Starting a while-loop
  while True: 
     # Asking for input(a and b)
     a = int(input('enter a number'))
     b = int(input('enter another number'))
     # If a is bigger than print('bigger than b')
     if a>b:
         print('a is bigger then b')
     # Otherwise...
     else:
         print('b is bigger than a')
     # Start all over again from a = int(input('enter a number'))

Now I don't want to entirely stop the loop using break or condition = True. I just want the loop to start all over again. If you want any clarifications, feel free to ask

Upvotes: 2

Views: 4711

Answers (3)

Yash Khasgiwala
Yash Khasgiwala

Reputation: 711

Use a counter that will input values continuously and print only once.

i=1
while True:

     # Asking for input(a and b)
     a = int(input('enter a number'))
     b = int(input('enter another number'))
     if i==1:
        i=i+1
        if a>b:
             print('a is bigger then b')
        else:
             print('b is bigger than a')
     else:
         continue

Upvotes: 1

AnsFourtyTwo
AnsFourtyTwo

Reputation: 2518

To execute some block of code only once within an endless while loop, you need to use a flag like in the example below:

printed_flag = False
while True:
    a = int(input('enter a number'))
    b = int(input('enter another number'))

    if printed_flag:
        if a>b:
            print('a is bigger then b')
        else:
            print('b is bigger than a')
        printed_flag = False

Upvotes: 3

R_Creation92
R_Creation92

Reputation: 13

You can add in a counter to repeat the loop until the counter stops. What was done below is to set the counter to infinity.

i = 0
while i <= float("inf"):
    i += 1
    a = int(input('enter a number'))
    b = int(input('enter another number'))

    if a>b:
        print('a is bigger then b')
    else:
        print('b is bigger than a')

Upvotes: 1

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