CODEWITHSUNDEEP
python
Sara Simon
Sara Simon

Reputation: 31

UnboundLocalError: local variable 'text' referenced before assignment

How do you fix this error?

Here is my code:

even = None
def is_even(num):
    if num % 2 == 0:
        even = True
        return even
    elif num % 2 != 0:
        even = False
        return even

def lastmes():
    if even == True:
        text = "The last value of even is True"
    elif even == False:
        text = "The last value of even is False"
    return text

print(lastmes())
print(is_even(51))

Here is my error message:

Traceback (most recent call last):
  File "main.py", line 17, in <module>
    print(lastmes())
  File "main.py", line 15, in lastmes
    return text
UnboundLocalError: local variable 'text' referenced before assignment

Upvotes: -1

Views: 4023

Answers (2)

Ghost
Ghost

Reputation: 735

You should do 3 things.

First, make even variable inside the is_even function global. You are just creating another local variable and setting it's value which wont change the even you created outside the function.

def is_even(num):
    global even #Here
    if num % 2 == 0:
        even = True
        return even
    elif num % 2 != 0: #You should change this to just an else but this works too
        even = False
        return even

Second, change the elif in your lastmes function to else. If you plan on using elif and want to consider a possibility for even to be None, then you should add another else to deal with the None possibility.

def lastmes():
    if even == True:
        text = "The last value of even is True"
    else:
        text = "The last value of even is False"
    return text

Third, call is_even before lastmes so that the values are calculated, before checking them and displaying the messages.

print(is_even(50))
print(lastmes())

Upvotes: 2

kindall
kindall

Reputation: 184465

If even is neither True nor False, then text is never defined. even is set to None at the beginning of your program.

Upvotes: 1

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