CODEWITHSUNDEEP
pythondatetime
SahilM
SahilM

Reputation: 128

Issues with Comparing DateTime

I am currently trying to compare an array of times with current time and execute certain code.

import os
import datetime as dt

t1 = dt.time(hour=12, minute=45)
t2 = dt.time(hour=12, minute=47)
timetable = [t1, t2]

for i in timetable:
    if i[0,1] == dt.datetime.now().hour and i[2,4] == dt.datetime.now().minute:
        print("Its working...")

    else:
        print ("time is now changed")

Currently giving the format like above for specific times. I tried entering time as string like timetable = ["12:45", "12:50"] or integer as timetable = [(12),(45),(12),(50)]

but all methods give me different errors.

Upvotes: 0

Views: 122

Answers (3)

정도유
정도유

Reputation: 559

timetable = ["12:45", "12:50"]

for i in timetable:
    hour, minute = i.split(':')
    if int(hour) == dt.datetime.now().hour and int(minute) == dt.datetime.now().minute:
        print("Its working...")

    else:
        print ("time is now changed")

Upvotes: 1

Leogout
Leogout

Reputation: 1247

If you do this:

import datetime as dt

t1 = dt.time(hour=12, minute=45)
t2 = dt.time(hour=12, minute=47)
timetable = [t1, t2]

In your array timetable, your now have two times.

When you iterate over this array, in your i you have one time, and then the other. In python, you can actually directly compare times together:

for i in timetable:
    # i is a datetime here, you can't access its content with i[0, 1] or anything
    # to copare it with the time now, you can do this instead:
    if i > dt.datetime.now().time():
        # do stuff

Upvotes: 1

Isaac Ng
Isaac Ng

Reputation: 86

Change this

if i[0,1] == dt.datetime.now().hour and i[2,4] == dt.datetime.now().minute:

to

if i.hour == dt.datetime.now().hour and i.minute == dt.datetime.now().minute:

timetable contains two datetime objects, not four separate strings of h, m, h, m.

For example, the first i would be datetime(hour=12, minute=45), so extract hour from it with i.hour.

Upvotes: 1

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