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javascriptarraysobjectarray-map
thednp
thednp

Reputation: 4479

JavaScript: find Object with highest summed values from Array

In need the Object with maximum a+b value from myArray

var myArray = [{a:5,b:10},{a:10,b:7},{a:8,b:5}];

Right now I have something that returns me the index:

var max = [], maxIndex;
myArray.map(x=>max.push(x.a + x.b))
maxIndex = max.indexOf( Math.max.apply(Math, max))

I need something that returns the Object and not its index, so far working with

var maxObject = myArray.map(x=>x.a + x.b).reduce((x,y)=>x>y)

returning false.

Upvotes: 1

Views: 355

Answers (4)

JaroF
JaroF

Reputation: 68

No need for map as reduce will itterate over you array.

var myArray = [{a:5,b:10},{a:10,b:7},{a:8,b:5}];


var biggestSumObj = myArray.reduce((total,current)=>{
  if((current.a + current.b) > (total.a + total.b)){
    return current;
  }
  return total;
});


console.log(biggestSumObj);

fiddle: return biggest object

Upvotes: 1

Nathan Barel
Nathan Barel

Reputation: 388

Based on your code, after you found the index of the object with the highest summed values , you simply return the array in that index:

var myArray = [{a:5,b:10},{a:10,b:7},{a:8,b:5}];
var max = [],
  maxIndex;
var result;
myArray.map(x => max.push(x.a + x.b))
maxIndex = max.indexOf(Math.max.apply(Math, max))
result = myArray[maxIndex];
console.log(result);

Upvotes: 0

Mehmet Ali
Mehmet Ali

Reputation: 363

You may try something like that:

let myArray = [{a:5,b:10},{a:10,b:7},{a:8,b:5}];
let max = myArray[0].a + myArray[0].b;
let maxObject = {...myArray[0]};
    
myArray.map((obj) => {
   if(max < obj.a + obj.b) {
       max = obj.a + obj.b;
       maxObject = {...obj}
    }
});
    
console.log(maxObject); // { a: 10, b: 7 }

Upvotes: 0

Nithish
Nithish

Reputation: 6009

You can use reduce like below

var myArray = [{a:5,b:10},{a:10,b:7},{a:8,b:5}];

const finalResult = myArray.reduce((result, obj) => {
  let sum = obj.a + obj.b;
  if(result.sum < sum) {
    return {sum, obj: {...obj}}
  } 
  return result;
}, {sum: 0, obj: {}})

console.log(finalResult.obj)

Hope this helps.

Upvotes: 2

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