CODEWITHSUNDEEP
pythonregex
Phoenix
Phoenix

Reputation: 4284

How can ignore spaces with re module

Here is my regex to detect expressions like {{ value1 | value2 }}:

p="\{{\{{\s*{tag_key}\s*([^\|\}}]+)\s*\|\s*([^\|\{{]+)\s*\}}\}}".format(tag_key="name")

It's totally fine where there are some spaces between value1

In [1]: re.sub(p, "REPLACED", "content: {{ name |default_value}}")                                                                                               
Out[1]: 'content: REPLACED'

Or

In [2]: re.sub(p, "REPLACED", "content: {{  name  |default_value}}")                                                                                               
Out[2]: 'content: REPLACED'

But what I want is my pattern acts the same either there are spaces or not.

In [3]: re.sub(p, "REPLACED", "content: {{name|default_value}}")                                                                                               
Out[3]: 'content: {{name|default_value}}'

Any help would be appreciated!

Upvotes: 0

Views: 52

Answers (1)

jdaz
jdaz

Reputation: 6053

It wasn’t working without spaces because you had an extra ([^\|\}}]+) that you didn’t need, which was requiring a space to be present. Here’s what I would recommend:

p = r"{{\s*" + tag_key + r"\s*\|\s*([^\|}]+)\s*}}"

This way the braces {} from the Python string format function don’t have a chance to throw you off either.

Upvotes: 1

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