Reputation: 3
with smtplib.SMTP('smtp.gmail.com', 587) as smtp:
server = smtplib.SMTP('smtp.gmail.com', 587)
smtp.ehlo()
smtp.starttls()
smtp.ehlo()
msg = MIMEMultipart()
smtp.login(EMAIL_ADRESS, EMAIL_PASSWORD)
subject = 'Log Register'
filename = 'logs-to-h4wtsh0wt.txt'
attachment = open(filename, 'rb')
part = MIMEBase('application', 'octet-stream')
part.set_payload(attachment.read())
encoders.encode_base64(part)
part.add_header('Content-Disposition', "attachment; filename= "+filename)
msg.attach(part)
msg = f'Subject: {subject}\n\n{Body}'
smtp.sendmail(EMAIL_ADRESS,EMAIL_ADRESS, msg)
Upvotes: 0
Views: 1248
Reputation: 76
snakecharmerb is right. You are indeed overriding the message object and therefore losing everything you add before that point.
You can instead set the subject like this:
msg['Subject'] = "Subject of the Mail"
# string to store the body of the mail
body = "Body_of_the_mail"
# attach the body with the msg instance
msg.attach(MIMEText(body, 'plain'))
Because you are attaching a file you will also need to convert the multipart message into a string before sending:
text = msg.as_string()
smtp.sendmail(fromaddr, toaddr, text)
When you created msg
with MIMEMultipart()
it generated the message object structure for you as per RFC2822 which also gives you FROM
, TO
, etc.
The msg object also has a bunch of functions you can run outlined in its docs
Upvotes: 2