CODEWITHSUNDEEP
javaspringspring-bootspring-mvcspring-rest
sateesh kumar Rayapati
sateesh kumar Rayapati

Reputation: 65

How to read the @Request Param attribute values that contains ampersand (&) in Spring Boot Rest API

Team,

When i try to read the Request Param attribute values that contains ampersand (&) in spring Boot rest api i am getting Number Format Exception. Below is sample code which i tried. Please Suggest me on this.

Request URL : http://loacalhost:8080/search/ad?skey="uc"&fn="M&M"

Rest Controller method:

@GetMapping(value = "/search/ad")
public ResponseEntity<List<SearchResultDTO>> findSearchResult(
            @RequestParam(value="skey",required=true) String skey,
            @RequestParam(value="fn",required=false,defaultValue = "null") String fn
            ) {
.....
}

Exception is : "java.lang.NumberFormatException: For input string: "M&M""

I tried below ways also :

fn="M%26M" , fn=""M%26amp;M" , fn=""M&M" in each case below was the exception i am getting.

"java.lang.NumberFormatException: For input string: "M%26M"", "M%26amp;M"" "M&M""

As suggested i tried below .

@SpringBootTest(classes = Application.class, webEnvironment = SpringBootTest.WebEnvironment.RANDOM_PORT) public class SearchIntegrationTest {

@LocalServerPort
private int port;

@Autowired
TestRestTemplate testRestTemplate;

@Test
public void findearchResult_IntegrationTest() throws JSONException {

    String url = UriComponentsBuilder.fromUriString("/search/ad").queryParam("skey", "uc")
            .queryParam("pf", "C&S").encode().toUriString();

    ResponseEntity<String> response = testRestTemplate.getForEntity(url, String.class);

    assertEquals(HttpStatus.OK, response.getStatusCode());

}

}

Error is: java.lang.NumberFormatException: For input string: "C%26S"

Upvotes: 3

Views: 1574

Answers (2)

Vielen Danke
Vielen Danke

Reputation: 187

Try this:

@GetMapping("/example")
public Map<String, String[]> getExample(HttpServletRequest request) {
    return request.getParameterMap();
}

And the URI would be:

?skey="uc"&fn="M%26M"

And the response in JSON format

{
    "skey": [
        "\"uc\""
    ],
    "fn": [
        "\"M&M\""
    ]
}

You also can extract the single parameter if you know it's name by using

request.getParameter("skey");

Upvotes: 1

Abhinaba Chakraborty
Abhinaba Chakraborty

Reputation: 3671

You have to do URL encoding when sending the request. If you are testing the API manually, then you have to encode it yourself.

eg.

http://loacalhost:8080/search/ad?skey="uc%26fn%3D%22M%26M"

Else if you are using RestTemplate to test this API, then you can use something like this:

eg.

String url = UriComponentsBuilder
        .fromUriString("http://loacalhost:8080/search/ad")
        .queryParam("skey", "uc&fn=\"M&M").encode().toUriString();
new RestTemplate().getForEntity(url, String.class).getBody();

Upvotes: 0

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