Reputation: 13255
I have a nested HashMap
with String
keys that contains either List
, Map
, or String
values. I would like to flatten them like the below.
Here is the data:
import java.util.*;
import java.util.stream.*;
public class MyClass {
public static void main(String args[]) {
Map<String, Object> dates = new HashMap<String, Object>() {{
put("1999", new HashMap<String, Object>() {{
put("3", Arrays.asList("23", "24", "25"));
put("4", Arrays.asList("1", "2", "3"));
}});
put("2001", new HashMap<String, Object>() {{
put("11", new HashMap<String, Object>() {{
put("7", Arrays.asList("23", "24", "25"));
put("9", Arrays.asList("1", "2", "3"));
}});
put("12", "45");
}});
}};
System.out.println(dates);
}
}
Map looks like:
{2001={11={7=[23, 24, 25], 9=[1, 2, 3]}, 12=45},
1999={3=[23, 24, 25], 4=[1, 2, 3]}}
The flattening of map should look like this:
{2001.11.7.1=23, 2001.11.7.2=24, 2001.11.7.3=25, 2001.11.9.1=1, 2001.11.9.2=2,
2001.11.9.3=3, 2001.12=45, 1999.3.1=23, 1999.3.2=24, 1999.3.3=25,
1999.4.1=1, 1999.4.2=2, 1999.4.3=3}
Note: the level of nested arrays or maps is unknown, it may go more than 2 levels.
Upvotes: 4
Views: 1920
Reputation: 864
private static Map<String, String> flatten(Map<String, Object> m) {
var pairs = new ArrayList<String[]>();
flatten(null, m, pairs);
return pairs.stream().collect(Collectors.toMap(x -> x[0], x -> x[1]));
}
private static void flatten(String prefix, Map<String, Object> m, List<String[]> pairs) {
for (var e : m.entrySet()) {
var k = e.getKey();
var o = m.get(k);
if (o instanceof String s) {
pairs.add(new String[]{makeKey(prefix, k), s});
} else if (o instanceof List l) {
IntStream.range(0, l.size())
.mapToObj(i -> new String[]{
makeKey(prefix, k + "." + (i +1)),
l.get(i).toString()
})
.forEach(p -> pairs.add(p));
} else if (o instanceof Map nestedMap) {
flatten(makeKey(prefix, k), nestedMap, pairs);
}
}
}
private static String makeKey(String prefix, String key) {
return String.join(".", prefix == null ? List.of(key) : List.of(prefix,key));
}
Upvotes: 0
Reputation:
You can iterate over this map, and process each entry value, depending on its instance of: Map
, List
, or String
. Since the level of nested arrays or maps is unknown, I have modified a little your code example and flat map format for clarity, also I used TreeMap
instead of HashMap
for entries ordering.
public static void main(String[] args) {
TreeMap<String, Object> treeMap = new TreeMap<String, Object>() {{
put("1999", new TreeMap<String, Object>() {{
put("3", Arrays.asList("23", "24", "25"));
put("4", Arrays.asList("1", "2", new TreeMap<String, Object>() {{
put("10", "42");
}}));
}});
put("2001", new TreeMap<String, Object>() {{
put("11", new TreeMap<String, Object>() {{
put("7", Arrays.asList("23", "24", "25"));
put("9", Arrays.asList("1", "2", "3"));
}});
put("12", "45");
}});
}};
TreeMap<String, String> flatMap = new TreeMap<>();
processMap("", treeMap, flatMap);
System.out.println(treeMap);
System.out.println(flatMap);
}
private static void processMap(String prefix,
Map<String, Object> map,
Map<String, String> flatMap) {
for (Map.Entry<String, Object> entry : map.entrySet()) {
String key = entry.getKey();
Object value = entry.getValue();
processEntry(prefix, key, value, flatMap);
}
}
private static void processList(String prefix,
List<Object> list,
Map<String, String> flatMap) {
for (int i = 0; i < list.size(); i++) {
String key = String.valueOf(i + 1);
Object value = list.get(i);
processEntry(prefix, key, value, flatMap);
}
}
@SuppressWarnings("unchecked")
private static void processEntry(String prefix,
String key,
Object value,
Map<String, String> flatMap) {
if (value instanceof Map) {
processMap(prefix + key + ".", (Map<String, Object>) value, flatMap);
} else if (value instanceof List) {
processList(prefix + key + ":", (List<Object>) value, flatMap);
} else if (value instanceof String) {
flatMap.put(prefix + key, (String) value);
}
}
Sample map:
{1999={3=[23, 24, 25], 4=[1, 2, {10=42}]},
2001={11={7=[23, 24, 25], 9=[1, 2, 3]}, 12=45}}
Flattened map:
{1999.3:1=23, 1999.3:2=24, 1999.3:3=25, 1999.4:1=1, 1999.4:2=2, 1999.4:3.10=42,
2001.11.7:1=23, 2001.11.7:2=24, 2001.11.7:3=25,
2001.11.9:1=1, 2001.11.9:2=2, 2001.11.9:3=3, 2001.12=45}
Opposite: Restoring a value tree from its flat map representation.
Upvotes: 1
Reputation: 89139
You can use recursion to flatten the Map
. Each time you encounter a Map
, recurse by flattening that Map
; when you encounter a List
, iterate over it and add the index to the current key. A single value can be trivially set otherwise. See the below code in action here.
public static Map<String, Object> flatten(final Map<String, Object> map) {
return flatten("", map, new HashMap<>());
//use new TreeMap<>() to order map based on key
}
@SuppressWarnings("unchecked")//recursive helper method
private static Map<String, Object> flatten(final String key, final Map<String, Object> map,
final Map<String, Object> result) {
final Set<Map.Entry<String, Object>> entries = map.entrySet();
if (!entries.isEmpty()) {
for (final Map.Entry<String, Object> entry : entries) {
//iterate over entries
final String currKey = key + (key.isEmpty() ? "" : '.') + entry.getKey();
//append current key to previous key, adding a dot if the previous key was not an empty String
final Object value = entry.getValue();
if (value instanceof Map) {//current value is a Map
flatten(currKey, (Map<String, Object>) value, result);//flatten Map
} else if (value instanceof List) {//current value is a List
final List<Object> list = (List<Object>) value;
for (int i = 0, size = list.size(); i < size; i++) {
result.put(currKey + '.' + (i + 1), list.get(i));
}
//iterate over the List and append the index to the current key when setting value
} else {
result.put(currKey, value);//set normal value
}
}
}
return result;
}
public static void main(final String[] args){
final Map<String, Object> flattened = flatten(dates);
System.out.println(flattened);
}
Upvotes: 2