Reputation: 83
I have a list:
l = [['a', []], ['b', []], ['c', []], ['d', ['c']], ['e', ['d']], ['f', []], ['g', ['f', 'a', 'e']], ['h', ['g']]]
I want to count how many times an element doesn't appear in another list, for example in this list it would be b and h.
These are the only elements that appear only one time in all the list , so the function would return 2.
Another example:
l2 = [['a', []], ['b', []], ['c', ['b']], ['d', ['c', 'b', 'a']], ['f', ['d']], ['g', ['f', 'a']], ['h', ['f', 'c']], ['i', ['h', 'a']]]
Here we got 2 elements that appear only one time in all the lists: g and i
I want to use the python function count but I don't really know how to apply it in this case.
Upvotes: 0
Views: 151
Reputation: 479
Hello based on what you requested I have made a function that I called count(matrix) it returns an array of char that exist once in the matrix provided as a paramter
def count(matrix):
result=[]
removed= []
for line in matrix:
if line[0] in result :
result.remove(line[0])
elif line[0] not in removed:
result.append(line[0])
removed.append(line[0])
for e in line[1]:
if e in result :
result.remove(e)
elif e not in removed:
result.append(e)
removed.append(e)
return result
Hope this was useful
Upvotes: 1
Reputation: 85
n contains the elements that appear only once
l = [['a', []], ['b', []], ['c', []], ['d', ['c']], ['e', ['d']], ['f', []], ['g', ['f', 'a', 'e']], ['h', ['g']]]
m = []
n = []
counter = []
for i in l:
m.append(i[0])
for j in i[1]:
m.append(j)
m.sort()
for i in m:
count = 0
for j in m:
if i == j:
count += 1
counter.append(count)
n = [m[i] for i in range(0,len(m)) if counter[i] == 1]
Upvotes: 1