CODEWITHSUNDEEP
pythonpython-3.xif-statementbitwise-operators
itsyoboimananshah
itsyoboimananshah

Reputation: 11

Bitwise Operator with If Statement and comparison Operators. How does this if statement work?

a = 2
b = 1
if a == 2 | b == 1:
    print(a, b)

this won't print the values of a & b

a = 2
b = 1
if ((a == 2) | (b == 1)):
    print(a, b)

this will print the values

why so?

Upvotes: 1

Views: 394

Answers (2)

Suraj
Suraj

Reputation: 2477

| is the bitwise OR operator and it has higher precedence than ==. So if brackets are not used, 2 | b is executed at the start in the first program.

(2 | b) -> (2 | 1) -> (3)

Then when a==3 is checked, it returns False, since a=2

I think you could use the or instead of | here if you want to to execute the statement by checking values of a and b.

Upvotes: 1

DYZ
DYZ

Reputation: 57033

Operator == in Python has a lower precedence than the operator |. So:

a == 2 | b == 1

is equivalent to:

a == (2 | b) == 1

which, in turn, is equivalent to:

(a == (2 | b)) and ((2 | b) == 1)

Given that a==2, at least one of the subexpressions must be false, regardless of b.

Upvotes: 5

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