Having trouble locating logically error, for loop with recursion

Question

My goal is to print numbers from 1 to 9 with no repeats using the logic: for each number in the array to be printed,

• check all numbers in that row of the array if there is a repeated number

• else re-roll the random number perform these tasks recursively until whole row is filled from 1-9 with no repeated number

    p = np.zeros((1,9), dtype=int)
  
    def check_row(i):
      num = random.randint(1,9)
      # check num equal any number in its row
      for nine in range(9):
        if num == p[i][nine]:
            check_row(i)  
        else:
            pass    
      return num
  
   for j in range(9):
     if p[0][j] == 0:
       p[0][j] = check_row(0)
  
   print(p)
  

Answer 1

p = np.zeros((1,9), dtype=int)

  def check_row(i):
    num = random.randint(1,9)
    # check num equal any number in its row
    for nine in range(9):
      if num == p[i][nine]:
          num = check_row(i)  
      else:
          pass    
    return num

 for j in range(9):
   if p[0][j] == 0:
     p[0][j] = check_row(0)

 print(p)