Reputation: 1
Given, for example, the expression (3*cos(pi*n/2)+2*sin(pi*n/2))/n**2
and the knowledge that n is a positive odd integer (ie 1,3,5,...), the expression could simplify to 2*(-1)**((n-1)/2)/n**2
because the cos(pi*n/2)
terms all go to zero, and the sin(pi*n/2)
terms go to -1 or +1. Is there any way I can make sympy recognise this fact and perform the simplification?
Upvotes: 0
Views: 244
Reputation: 14530
You can declare n
to be odd
:
In [72]: n = Symbol('n', odd=True)
In [73]: (3*cos(pi*n/2)+2*sin(pi*n/2))/n**2
Out[73]:
n 1
─ - ─
2 2
2⋅(-1)
───────────
2
n
Upvotes: 0