CODEWITHSUNDEEP
javascriptnode.jsarraysdatetimeobject
pse
pse

Reputation: 151

Array sorting according to time in string

I have an array of objects. I want to sort the array according to the object key. For example below -

{
   "id": 3511,
   "time": "03:30",
   "hour": 3,
   "utc_date_time": "2020-07-07T02:07:54.000Z",
   "members": 0
},
{
   "id": 3514,
   "time": "04:30",
   "hour": 4,
   "utc_date_time": "2020-07-07T02:07:54.000Z",
   "members": 0
},
{
   "id": 3513,
   "time": "04:00",
   "hour": 4,
   "utc_date_time": "2020-07-07T02:07:54.000Z",
   "members": 0
},

I want to sort it according to time like this-

{
   "id": 3511,
   "time": "03:30",
   "hour": 3,
   "utc_date_time": "2020-07-07T02:07:54.000Z",
   "members": 0
},
{
   "id": 3513,
   "time": "04:00",
   "hour": 4,
   "utc_date_time": "2020-07-07T02:07:54.000Z",
   "members": 0
},
{
   "id": 3514,
   "time": "04:30",
   "hour": 4,
   "utc_date_time": "2020-07-07T02:07:54.000Z",
   "members": 0
},

I have used this function to sort but it is not giving the expected output I have also used the time key, still the same.

timeSlots.sort(function(a, b) {
  return a.time- b.time;
});

But not getting an expected output.

Upvotes: 0

Views: 851

Answers (4)

Sumanth Yedoti
Sumanth Yedoti

Reputation: 29

Your can pass a compare function to sort method saying how you want to sort the array elements. Thus, it provides a way to sort objects too.

To sort in ascending order:

const sortedArrayOfObjects = array.sort((item1, item2) => {
    if(item1.id < item2.id) return -1
    else if(item1.id > item2.id) return 1
    else return 0;
});
  • If compareFunction(a, b) returns less than 0, sort a to an index lower than b (i.e. a comes first).
  • If compareFunction(a, b) returns 0, leave a and b unchanged with respect to each other, but sorted with respect to all different elements.
  • If compareFunction(a, b) returns greater than 0, sort b to an index lower than a (i.e. b comes first).

Upvotes: 0

erani_246
erani_246

Reputation: 215

let arr =    [{
        "id": 3511,
        "time": "03:30",
        "hour": 3,
        "utc_date_time": "2020-07-07T02:07:54.000Z",
        "members": 0
    },
    {
        "id": 3514,
        "time": "04:30",
        "hour": 4,
        "utc_date_time": "2020-07-07T02:07:54.000Z",
        "members": 0
    },
    {
        "id": 3513,
        "time": "04:00",
        "hour": 4,
        "utc_date_time": "2020-07-07T02:07:54.000Z",
        "members": 0
    }]
    

sortedArr = arr.sort(function(a, b){
                if (a['time'] < b['time']) return -1;
                if (a['time'] > b['time']) return 1;
                return 0
           })

console.log(`sorted: `, sortedArr);

Upvotes: 0

ZephDavies
ZephDavies

Reputation: 4554

Lodash's "sortBy" is perfect for this.

_.sortBy(timeSlots, 'time');

Upvotes: 1

Nick
Nick

Reputation: 147206

Since your .time values are in HH:MM format, you can sort them as strings:

let array = [{
    "id": 3511,
    "time": "03:30",
    "hour": 3,
    "utc_date_time": "2020-07-07T02:07:54.000Z",
    "members": 0
  },
  {
    "id": 3514,
    "time": "04:30",
    "hour": 4,
    "utc_date_time": "2020-07-07T02:07:54.000Z",
    "members": 0
  },
  {
    "id": 3513,
    "time": "04:00",
    "hour": 4,
    "utc_date_time": "2020-07-07T02:07:54.000Z",
    "members": 0
  }
];

array.sort((a, b) => a.time.localeCompare(b.time));
console.log(array);

Upvotes: 3

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