Reputation:
I'm attempting to check if a user's ID is in this array and if they are, also get the "text" from it.
Array:
const staff = [
{
user: '245569534218469376',
text: 'dev'
},
{
user: '294597887919128576',
text: 'loner'
}
];
I've tried if (staff.user.includes(msg.member.id))
(Which I didn't think was going to work, and didn't.)
Upvotes: 0
Views: 854
Reputation: 51
One another way to do that is:
const inArray = (array, id) => array.filter(item => item.user === id).length >= 1;
const users = [
{
user: '245569534218469356',
text: 'foo'
}, {
user: '245564734218469376',
text: 'bar'
}, {
user: '246869534218469376',
text: 'baz'
}
];
console.log(inArray(users, '246869534218469376')); // true
console.log(inArray(users, '222479534218469376')); // false
Upvotes: 0
Reputation: 146219
You may try something like this:
const staff = [
{
user: '245569534218469376',
text: 'dev'
},
{
user: '294597887919128576',
text: 'loner'
}
];
let item = staff.find(item => item.user == '294597887919128576'); // msg.member.id
if (item) {
console.log(item.text);
}
Upvotes: 0
Reputation: 753
const findUser = (users, id) => users.find(user => user.id === id)
const usersExample = [
{
id: '123456765',
text: 'sdfsdfsdsd'
},
{
id: '654345676',
text: 'fdgdgdg'
}
]
//////////////////
const user = findUser(usersExample, '123456765')
console.log(user && user.text)
Upvotes: 0
Reputation: 21638
The some method on an array is used to tell if an item meets a condition, it is similar to the find method but the find method returns the item where the some method return true or false.
const staff = [
{
user: '245569534218469376',
text: 'dev'
},
{
user: '294597887919128576',
text: 'loner'
}
];
const isStaff = (staff, id) => staff.some(s => s.user === id);
console.log(isStaff(staff, '123'));
console.log(isStaff(staff, '245569534218469376'));
Upvotes: 0