CODEWITHSUNDEEP
javascriptarrays
Kaniel Outis
Kaniel Outis

Reputation: 25

Filter array of words based on array of endings

I would like to compare two lists with Javascript. I want to output everything from WORDLIST that contains END. (should not be in the middle of the word, but the last characters)

jQuery would also work for me.

var WORDLIST = ['instagrampost', 'facebookpost', 'google']
var END = ['post', 'gle']

function compare() {
    var final = WORDLIST.endsWith(END, END.length);
    console.log(final);
}

// count the signs of end
// take wordlist and take end.lenght from behind
// save a word from the wordlist as result, if it contains a word from end as result

Upvotes: 2

Views: 566

Answers (2)

Greedo
Greedo

Reputation: 3549

Here a solution without regex, base on indexOf :

var WORDLIST = ['instagrampost', 'facele', 'facebookpost', 'google', 'dnuiwa']
var END = ['post', 'gle']

function endsWith(wordlist, end){
  return wordlist.filter((w) => 
    end.filter((e) => w.indexOf(e) == w.length - e.length).length > 0
  );
}

console.log(endsWith(WORDLIST, END))

Upvotes: 1

Yevhen Horbunkov
Yevhen Horbunkov

Reputation: 15530

You may Array.prototype.filter() your WORDLIST based on whether Array.prototype.some() item of END is an ending (String.prototype.endsWith()) of a word:

const WORDLIST = ['instagrampost', 'facebookposting', 'google'],
      END = ['post', 'gle'],
      
      result = WORDLIST.filter(w =>
        END.some(e => w.endsWith(e)))
        
console.log(result)

p.s. if you need case-insensitive match, you may do w.toLowerCase().endsWith(e.toLowerCase())

Upvotes: 4

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