CODEWITHSUNDEEP
pythonhtmlurlurllib
Stanyko
Stanyko

Reputation: 195

How to get right HTML code from a concrete URL (python)

Im trying to write a code, that will be able to verify domain through whois.domaintools.com.

But theres a little problem with reading the html, that do not match with whois.domaintools.com/notregistereddomain.com source code. Whats wrong? Its problem with requsting or what? I really dont know how to solve it.

import urllib2

def getPage():
    url="http://whois.domaintools.com/notregistereddomain.com"

    req = urllib2.Request(url)

    try:
        response = urllib2.urlopen(req)
        return response.read()
    except urllib2.HTTPError, error:
        print "error: ", error.read()
        a = error.read()
        f = open("URL.txt", "a")
        f.write(a)
        f.close()


if __name__ == "__main__":
    namesPage = getPage()
    print namesPage

Upvotes: 0

Views: 965

Answers (1)

Schnouki
Schnouki

Reputation: 7707

If you use print error instead of print error.read(), you'll see that you're getting a HTTP 403 "Forbidden" answer from the server.

Apparently this server doesn't like requests without a user-agent header (or it doesn't like Python's one because it doesn't want to be queried from a script). Here's a workaround:

user_agent = "Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)" # Or any valid user agent from a real browser
headers = {"User-Agent": user_agent}
req = urllib2.Request(url, headers=headers)
res = urllib2.urlopen(req)
print res.read()

Upvotes: 2

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