Reputation: 33072
In the following example I have in gold the intersection of 3 shapes (in this case I'm using circles but those 3 shapes can be anything) The golden intersection is the result of clipping with clip-path.
I would like to use the intersection as a symbol and for this I would need to know the bounding box of the intersection, i.e the red stroked rectangle.
If I'm using intersection.getBBox() I'm getting the bounding box before clipping.
How can I get the bounding box of the intersection?
console.log(intersection.getBBox())
svg{border:solid}
.circles{fill:none;stroke:black}
<svg id="svg" viewBox="-150 -150 300 300" width="300">
<defs>
<circle id="c1" cx="0" cy="-50" r="80"></circle>
<circle id="c2" cx="43.3" cy="25" r="80"></circle>
<circle id="c3" cx="-43.3" cy="25" r="80"></circle>
<clipPath id="clipC2"><use xlink:href="#c2"/></clipPath>
<clipPath id="clipC3"><use xlink:href="#c3"/></clipPath>
</defs>
<g class="circles">
<use xlink:href="#c1"/>
<use xlink:href="#c2"/>
<use xlink:href="#c3"/>
</g>
<g id="intersection">
<g clip-path="url(#clipC3)">
<use fill="gold" xlink:href="#c1" clip-path="url(#clipC2)"/>
</g>
</g>
<rect x="-38" y="-42" width="75" height="74" stroke="red" fill="none"/>
</svg>
Upvotes: 2
Views: 409
Reputation: 33072
The main idea is this:
src
attribute of an image.canvas
with the same size as the svg element.//the svg's viewBox
let vB = { x: -100, y: -100, w: 200, h: 200 };
//canvas
let ctx = c.getContext("2d");
//set the size of the canvas equal to the size of the svg element
c.width = vB.w;
c.height = vB.h;
// draw the svg element on the canvas
let xml = new XMLSerializer().serializeToString(svg);
// make it base64 and use it as the src attribute of the image
let img=new Image()
img.src = "data:image/svg+xml;base64," + btoa(xml);
img.onload = function() {
//paint the image on the canvas
ctx.drawImage(this, 0, 0);
//get the image data from the canvas
let imgData = ctx.getImageData(0, 0, vB.w, vB.h).data;
// x the smallest x value of a black pixel
// y the smallest y value of a black pixel
// X the biggest x value of a black pixel
// Y the biggest y value of a black pixel
let x = vB.w,
y = vB.h,
X = 0,
Y = 0;
let n = 0;
for (let i = 0; i < imgData.length; i += 4) {
n++
if (imgData[i + 3] != 0) {
//if the alpha (i+3) value of the pixel is not 0
let _y = Math.ceil(i / (4 * vB.w));
let _x = (i / 4) % vB.w;
if (_x < x) { x = _x; }
if (_y < y) { y = _y; }
if (_x > X) { X = _x; }
if (_y > Y) { Y = _y; }
}
if(n==imgData.length/4){
let newViewBox = `${x + vB.x} ${y + vB.y} ${X - x + 1} ${Y - y}`;
reuleaux.setAttribute("viewBox", newViewBox);
console.log(`viewBox="${newViewBox}"`);
}
}
}
svg,
canvas {
outline: 1px solid;
}
<svg id="svg" viewBox="-100 -100 200 200" width="200">
<defs>
<circle id="c1" cx="0" cy="-50" r="80"></circle>
<circle id="c2" cx="43.3" cy="25" r="80"></circle>
<circle id="c3" cx="-43.3" cy="25" r="80"></circle>
<clipPath id="clipC2"><use xlink:href="#c2"/></clipPath>
<clipPath id="clipC3"><use xlink:href="#c3"/></clipPath>
</defs>
<g id="intersection">
<g clip-path="url(#clipC3)">
<use xlink:href="#c1" clip-path="url(#clipC2)"/>
</g>
</g>
</svg>
<!--<img id="img" width="200" height="200"/>-->
<canvas id="c"></canvas>
<svg id="reuleaux" viewBox="-100 -100 200 200" width="200" style="background:#dfdfdf">
<use xlink:href="#intersection"/>
</svg>
Upvotes: 1
Reputation: 384
Unsure if this was the type of thing you were after.
let myBB = {
x: c2.getBBox().x,
get y() {
return c1.getBBox().y + this.width
},
get width() {
// return (posNum(c3.getBBox().x)) - (posNum(myBB.x));
let leftPointOfWidth = c2.getBBox().x;
let rightPointofWidth = c3.getBBox().x + c3.getBBox().width;
// 10000 to guarantee both positive numbers. very hacky
let mywidth = (rightPointofWidth + 10000) - (leftPointOfWidth + 10000);
return mywidth;
},
get height() {
return this.width;
}
}
I'm quite sure there's a better way to put it. And need to call the getters; They won't appear in the console.log(myBB)
Inputting the obtained coordinates and width gives the rect in yellow. (Pink rects are shoing centres of circles)
Upvotes: 0