CODEWITHSUNDEEP
pythonbeautifulsoupscreen-scraping
DJF
DJF

Reputation: 103

scraping with Beautiful Soup: print every other value in list off strings

I'm trying to pull 2019 CFB rankings but every other value is the next week's opponent and not the next team in the ranking. Is there a way to remove every other value without having to index the list?

base_site = "http://cbssports.com/college-football/rankings/cbs-sports-ranking/"

response = requests.get(base_site)
response

html = response.content

soup = bs(html, 'html.parser')

# Find all links on the page 
links = soup.find_all("span", {"class": 'TeamName'})
links

# Inspecting the text inside the links
[link.text for link in links]

response:

['LSU', 'UT-San Antonio', 'Clemson', 'Georgia Tech', 'Ohio St.', 'Bowling Green', 'Georgia', 'Virginia', etc.

With every other team as the ranking I need (LSU hen Clemson, etc.) Thanks

Upvotes: 0

Views: 36

Answers (1)

Edwin Cruz
Edwin Cruz

Reputation: 517

This shoudl do the trick.

names = ['LSU', 'UT-San Antonio', 'Clemson', 'Georgia Tech', 'Ohio St.', 'Bowling Green', 'Georgia', 'Virginia']

names = names[1::2]

The second element is chosen by indexing with 1, and then taken at an interval of 2.

Upvotes: 2

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