CODEWITHSUNDEEP
cpointersdynamic-memory-allocation
Newbie Engineer
Newbie Engineer

Reputation: 13

Declare and Initialize dynamic array of head nodes of linked lists

I would like to know how to declare, allocate and initialize array of Node to null.

typedef struct Nodes_Of_List { 
        int data; 
        struct Nodes_Of_List *next;
} Node;

//declare array of head nodes
Node *table;

//ALOCATE memory for "x" x is provided at runtime, number of head nodes
table = malloc(sizeof(Node) * x); 

//Initialize elements to Null value
?? //How to do it

Explanation regarding initializing dynamic array of head nodes of linked list to Null requested. Purpose is to make array of linked lists, to make a hashtable.

Upvotes: 0

Views: 345

Answers (1)

ThunderPhoenix
ThunderPhoenix

Reputation: 1883

Based on what I understood, you want to declare an array of head nodes. After that, you want to initialize them to NULL:

//declare array of head nodes statically
Node * table[x];      // x value provided at runtime
// Or dynamically
Node ** table = (Node **) malloc(sizeof(Node *) * x);
// Or use calloc directly wich will initialize your pointers to 0
Node ** table = (Node **) calloc(x, sizeof(Node *));

// table is an array of pointers. Each pointer references a linked list.
// Now you have just to put NULL value in each element of table
int i;
for(i = 0; i < x; i++) 
    table[i] = 0;

Upvotes: 1

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