CODEWITHSUNDEEP
spring-bootmultipartspring-testmockmvc
swapper9
swapper9

Reputation: 43

How to get MvcResult when unit testing POST with MultipartFile

When i'm testing just trivial POST-requests, i can get MvcResult and get something from it:

MvcResult result = mockMvc.perform(post("/api/register")
                .contentType(MEDIA_TYPE_JSON_UTF8)
                .content(new Gson().toJson(request)))
                .andExpect(status().isCreated())
                .andReturn();
Long tempId = Long.valueOf(JsonPath.read(result.getResponse().getContentAsString(), "$.id").toString());

But when i'm using MultipartFile, i can only use MockMvcRequestBuilders and only check expectations.

MockMultipartFile filePart = new MockMultipartFile(
                "file",
                "file.jpg",
                "image/jpeg", file);
mockMvc.perform(MockMvcRequestBuilders.multipart("/api/loadfile")
                .file(filePart)
                .param("json", json))
                .andExpect(status().isOk());

How can i get MvcResult with multipart POST after request?

Upvotes: 1

Views: 547

Answers (1)

rieckpil
rieckpil

Reputation: 12021

You can call .andReturn(); right after .andExpect() like you did it in the trivial POST example.

Calling mockMvc.perform() returns a ResultActions object independent of any HTTP method or request.

The following example works with Spring Boot 2.3.0:

byte[] file = new byte[10];
MockMultipartFile filePart = new MockMultipartFile(
  "file", "file.jpg", "image/jpeg", file);

MvcResult mvcResult = mockMvc.perform(MockMvcRequestBuilders.multipart("/api/loadfile")
  .file(filePart)
  .param("json", "json"))
  .andExpect(status().isOk())
  .andReturn();

Upvotes: 2

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