CODEWITHSUNDEEP
scalapathcompilationsbt
finite_diffidence
finite_diffidence

Reputation: 943

How to get parent directory of sbt file

I have the following line in my sbt file:

target in Compile in doc := baseDirectory.value / "docs"

This is creates a folder in the directory one level below the one I am aiming for. I would like to get essentially (pseudocode):

parentDirectory = parent of baseDirectory
target in Compile in doc := parentDirectory.value / "docs"

Where now "docs" sits next to the baseDirectory, as opposed to in it.

Is there an easy way to do this?

EDIT: Project Structure

myFolder/project/build.sbt

If I run "docs" in sbt shell, I get the following output:

myFolder/project/docs/

What I want instead is:

myFolder/docs/
myFolder/project/build.sbt

The reason I want to do this is so I can host my docs on github pages in the same directory. This seems the easiest way without complicating stuff.

Upvotes: 0

Views: 1321

Answers (2)

Mario Galic
Mario Galic

Reputation: 48420

Consider standard two successive dots .. notation to represent parent directory, for example

Compile / doc / target := baseDirectory.value / ".." / "docs"

Alternatively file("..") could also work

Compile / doc / target := file("../docs")

You might want to create a dedicated setting for reuse

lazy val parentOfBaseDirectory = settingKey[File]("Parent of base directory")
parentOfBaseDirectory := baseDirectory.value / ".."

Couple of side notes:

You can make quick one off experiments within sbt shell using set and semicolon ;

set Compile/doc/target := baseDirectory.value / ".." / "docs"; doc

The reason / syntax works is because File is implicitly converted to sbt's RichFile which provides additional useful extension methods.

Upvotes: 4

Matthias Berndt
Matthias Berndt

Reputation: 4587

baseDirectory.value is of type java.io.File, so you can use all these methods:

https://docs.oracle.com/javase/7/docs/api/java/io/File.html

The relevant one here would be getParentFile.

Upvotes: 1

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