Reputation: 261
I want to mimic URL encoding for Chinese characters. For my use case, I have a searching URL for a e-commerce site
'https://search.jd.com/Search?keyword={}'.format('ipad')
When I search a product in english, this works fine. However, I need to have input in Chinese, I tried
'https://search.jd.com/Search?keyword={}'.format('耐克t恤')
, and found the following encoding under the network tab
https://list.tmall.com/search_product.htm?q=%C4%CD%BF%CBt%D0%F4
So basically, I need to encode inputs like '耐克t恤' into '%C4%CD%BF%CBt%D0%F4'. I'm not sure which encoding the website is using? Also, how to convert Chinese characters to these encodings with python?
Update: I checked headers and it seems like content encoding is gzip?
Upvotes: 1
Views: 951
Reputation: 663
Try using the library urllib.parse
module. More specifically, urllib.parse.urlencode()
function. You can pass the encoding (in this case it appears to be 'gb2312') and a dict containing the query parameters to get a valid valid url suffix which you can use directly.
In this case, your code will look something like:
import urllib.parse
keyword = '耐克t恤'
url = 'https://search.jd.com/Search?{url_suffix}'.format(url_suffix=urllib.parse.urlencode({'keyword': keyword}, encoding='gb2312'))
More info about encoding here More info about urlencode here
Upvotes: 6
Reputation: 791
The encoding used seems to be GB2312
This could help you:
def encodeGB2312(data):
hexData = data.encode(encoding='GB2312').hex().upper()
encoded = '%' + '%'.join(hexData[i:i + 2] for i in range(0, len(hexData), 2))
return encoded
output = encodeGB2312('耐克t恤')
print(output)
url = f'https://list.tmall.com/search_product.htm?q={output}'
print(url)
Output:
%C4%CD%BF%CB%74%D0%F4
https://list.tmall.com/search_product.htm?q=%C4%CD%BF%CB%74%D0%F4
The only problem with my code is that it doesn't seem to 100% corrospond with the link you are trying to achieve. It converts the t
chacaracter into GB2312 encoding. While it seems to use the non encoded t
character in your link. Altough it still seems to work when opening the url.
Edit:
Vignesh Bayari R his post handles the URL in the correct (intended) way. But in this case my solution works too.
Upvotes: 2