CODEWITHSUNDEEP
pythonpython-3.xstringlistformat
YulkyTulky
YulkyTulky

Reputation: 1086

Replace nth Substring With nth Strings of Lists

I have a string like so:

"initWithType:bundleIdentifier:uniqueIdentifier:"

and two lists like so:

['long long', 'id', 'id']
['arg1', 'arg2', 'arg3']

and want to end up with the string:

"initWithType:(long long)arg1 bundleIdentifier:(id)arg2 uniqueIdentifier:(id)arg3"

As you may see, I effectively need to replace every nth semicolon with the nth string in each list (plus a little formatting with parentheses and a space).

I have been trying to use .format and the * unpacking operator but have had little success.

Upvotes: 1

Views: 49

Answers (1)

Selcuk
Selcuk

Reputation: 59219

You can use a combination of string formatting with zip:

s1 = "initWithType:bundleIdentifier:uniqueIdentifier:"
l2 = ['long long', 'id', 'id']
l3 = ['arg1', 'arg2', 'arg3']

print(" ".join("{}:({}){}".format(a, b, c) for a, b, c in zip(s1.split(":"), l2, l3)))

Edit: you can also use f-strings with Python >= 3.6 as suggested by @flakes:

print(" ".join(f"{a}:({b}){c}" for a, b, c in zip(s1.split(":"), l2, l3)))

this will print

initWithType:(long long)arg1 bundleIdentifier:(id)arg2 uniqueIdentifier:(id)arg3

Upvotes: 6

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