Reputation: 583
Writing a program to read a text file and storing it in a struct. An example of the text file:
chicken
dog
car
765
When there is some text in the line, it will get store into the struct. I have tried the following:
getline(file, aLine);
Info.animalchicken = aLine;
getline(file, aLine);
Info.animaldog = aLine;
getline(file, aLine);
Info.car = aLine;
getline(file, aLine);
Info.number = aLine;
I realised that the getline is literally getting every single line. When I run this in my program, the chicken will be stored in the struct Info.animalchicken. The next line, which is empty, will store into Info.animaldog. Dog will be stored in Info.car and so on.
I think a control loop is required here but can't think of a good one. How can I ignore the empty line so my text can enter into the struct correctly?
This is my struct
struct Info {
string animalchicken;
string animaldog;
string car;
int number;
}
Upvotes: 0
Views: 1022
Reputation: 117298
Here's an option adding stream operators and a helper function to skip empty lines.
#include <iostream>
#include <limits>
#include <sstream>
#include <string>
struct Info {
std::string animalchicken;
std::string animaldog;
std::string car;
int number;
};
// a helper function to do getline but skip empty lines
std::istream& getline_with_content(std::istream& is, std::string& s) {
while(std::getline(is, s)) if(not s.empty()) break;
return is;
}
// an istream operator to read one Info
std::istream& operator>>(std::istream& is, Info& i) {
getline_with_content(
getline_with_content(
getline_with_content(is,
i.animalchicken),
i.animaldog),
i.car);
is >> i.number;
// ignore everything after the number until a newline appears:
is.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
return is;
}
// an ostream operator to print one Info
std::ostream& operator<<(std::ostream& os, const Info& i) {
return os << i.animalchicken << '\n'
<< i.animaldog << '\n'
<< i.car << '\n'
<< i.number << '\n';
}
int main() {
// an example istream with a lot of blank lines:
std::istringstream file(
"chicken\n\n"
"dog\n\n"
"car\n\n\n"
"765\n");
Info i;
file >> i; // read one Info from the stream
std::cout << i; // print one Info
}
Upvotes: 0
Reputation: 39380
The loop idea, while quite primitive, should do the trick; the easiest way would be to wrap the logic in a separate function:
std::string getlineFilterEmpty(std::istream& s) {
std::string line;
do {
if (!s) {
throw std::runtime_error("End of stream");
}
getline(s, line);
} while(line.size() == 0);
return line;
}
Then getting your values is as simple as:
Info.animalchicken = getlineFilterEmpty(file);
Info.animaldog = getlineFilterEmpty(file);
Info.car = getlineFilterEmpty(file);
The number
member will require parsing the string to an integer, the code for which you'll find elsewhere on SO.
Upvotes: 1
Reputation: 33932
The logic needs to go something like,
Read a line. If read succeeded If line not empty Provide line Else Try again Else Handle error
Translating that into code and bundling it into a function for easy reuse, we get
std::string getNotEmptyLine(std::istream & in)
{
while (true) // repeat forever!
{
std::string temp;
std::getline(in, temp); // get a line
if (in) // test the line
{
if (line.size() != 0) // line not empty
{
return temp; //give it to caller
}
}
else
{
// handle error. We'll throw an exception, but this isn't the best solution
throw std::runtime_error("Couldn't read a line!");
}
}
}
As with all literal translations, it needs a bit of work. It would also be helpful to make this function work exactly like getline
so the caller can use it as a drop-in replacement.
std::istream & getNotEmptyLine(std::istream & in, // stream to read
std::string & line, // somewhere to put the string
char delim = '\n') // allow different delimiters
{
while (true) // repeat forever!
{
if (std::getline(in, line, delim)) // get a line right in line and test that we got it.
{
if (line.size() != 0) // line not empty
{
break; // success. exit.
}
}
else
{
// line will contain whatever this implementation of `getline` puts or
// leaves in the string on failure.
break; // fail. Let the caller decide what to do
}
}
return in;
}
Usage:
Info info;
std::string aLine;
if (getNotEmptyLine(in, info.animalchicken) &&
getNotEmptyLine(in, info.animaldog) &&
getNotEmptyLine(in, info.car) &&
getNotEmptyLine(in, aLine))
{
info.number = std::stoi(aLine);
}
else
{
// handle error
}
Note: even this may be too simplistic. It can't handle a line that contains nothing but whitespace. A single misplaced and nigh-invisible space will wreak havoc. If this is a concern, add more logic to if (line.size() != 0)
Upvotes: 0