CODEWITHSUNDEEP
javascriptarrays
thomalex
thomalex

Reputation: 69

Finding min and max in array Javascript

So I try to find the minimum and maximum if an array and want to call the function. I made this code, but it doesn´t work. I just don´t get why.

function getMinMax(arr){
  let maximum = Math.max(arr);
  let minimum = Math.min(arr);
 let result =  ([maximum, minimum]); 
  return result;
};

getMinMax([10,3,8,1,33])

Upvotes: 3

Views: 22354

Answers (6)

iopzhu
iopzhu

Reputation: 159

It's just ...

  Math.max(...arrayName)

If you want to use this method, you need to structure the array

function getMinMax(arr) {
    let maximum = Math.max(...arr);
    let minimum = Math.min(...arr);
    let result = [maximum, minimum];
    return result;
};

getMinMax([10, 3, 8, 1, 33]);

Upvotes: 2

Umutambyi Gad
Umutambyi Gad

Reputation: 4101

You can also try this simple and understandable math

Example

function max(arr) {
  let i;
  let max = arr[0]
  let min = arr[0]
  for (let i = 0; i < arr.length; i++) {
    if (arr[i] > max) {
      max = arr[i]
    } else if (arr[i] < min) {
      min = arr[i]
    }
  }
  let res = (["min: " + min, "max: " + max])
  return res
}

console.log(max([10, 3, 8, 1, 33]))

Upvotes: -1

Carsten Massmann
Carsten Massmann

Reputation: 28196

Or, as a one-liner (nothing new, only more compact):

const getMinMax=arr=>[Math.min(...arr),Math.max(...arr)];

console.log(getMinMax([10,3,8,1,33]))

Upvotes: 0

nima amr
nima amr

Reputation: 661

You can find the maximum and minimum in 2 ways. First way You go on with maximum and minimum form Math function in javascript, if you need to be used when you have to set numbers from max and min, like this :

let maximum = Math.max(10, 3, 8, 1, 33);
let minimum = Math.min(10, 3, 8, 1, 33);

Now you have an array so you have to convert to As above, for example : let array = [1,2,3,4,5] when you use ... before array you convert array to this : 1,2,3,4,5 for example :

function getMinMaxWithMath(arr){
  // Math.max(10,3,8,1,33)
  let maximum = Math.max(...arr);
  // Math.min(10,3,8,1,33)
  let minimum = Math.min(...arr);
 let result =  ([maximum, minimum]); 
  return result;
};

console.log('getMinMaxWithMath ', getMinMaxWithMath([10,3,8,1,33]));

The second way you can use for loop for example :

function getMinMaxForLoop(arr){
  let maximum = arr[0];
  let minimum = arr[0];
  for (let i = 0 ; i < arr.length; i++) {
    if (maximum < arr[i]) {
      maximum = arr[i];
    } else {
      minimum = arr[i];
    }
    
  }
 let result =  ([maximum, minimum]); 
  return result;
};
console.log('getMinMaxForLoop : ',getMinMaxForLoop([10,3,8,1,33]))

You can Look output from this link;

Upvotes: 4

Nicolae Maties
Nicolae Maties

Reputation: 2655

const getMinMax = (arr) => {
  const sortedArr = arr.sort((a,b) => a - b);
  const min = sortedArr[0];
  const max = sortedArr[sortedArr.length - 1];
  return [min, max];
};

console.log(getMinMax([10,3,8,1,33]))

You also can use Array.sort() to achieve your desired result.

Upvotes: 0

Sviatoslav Miller
Sviatoslav Miller

Reputation: 323

You try to pass array, but functions (min, max) accept only number arguments.

You need to unpack array to array of arguments with the spread operator (...):

const arr = [10, 3, 8, 1, 33];
const min = Math.min(...arr);
const max = Math.max(...arr);

So, your code should be like this:

function getMinMax(arr){
  let maximum = Math.max(...arr);
  let minimum = Math.min(...arr);
 let result =  ([maximum, minimum]); 
  return result;
};

getMinMax([10,3,8,1,33])

Upvotes: 5

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