CODEWITHSUNDEEP
pythonpython-3.x
bill_Pers
bill_Pers

Reputation: 17

How do I make a long binary into an array of 8 bits

I have a binary number val = 00111010011100011000000010100000000000100000111111010 i need to convert it to an array with 8 bit elements in it like arr = a= [{00111010},{01110001},...] is there a simple way to do so in python? Thanks in advance

Upvotes: 1

Views: 389

Answers (1)

ForceBru
ForceBru

Reputation: 44838

Use the & (bitwise AND) operator to extract the last 8 bits and the >> (bitwise right shift) to go through the bits:

>>> val = 0b00111010011100011000000010100000000000100000111111010
>>> f"{val & 0xff:08b}"
'11111010'
>>> val >>= 8 # shift 8 bits to the right
>>> bin(val)
'0b1110100111000110000000101000000000001000001'
>>> f"{val & 0xff:08b}"
'01000001'
>>> val >>= 8
>>> f"{val & 0xff:08b}"
'00000000'
>>> val >>= 8
>>> f"{val & 0xff:08b}"
'00010100'
>>>

Here 0xff == 0b11111111 (8 1 bits)

Upvotes: 2

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