CODEWITHSUNDEEP
pythondirectory
The Dan
The Dan

Reputation: 1680

Change base directory to upper directory in python

image

I am currently working inside the folder product_graph_analysis, specifically inside the file "database_functions.py" and when I configure my base directory:

import os
BASE_DIR = os.path.dirname(os.path.abspath(__file__))

whenever I want to set a path_file:

path_file = os.path.join(BASE_DIR, 'my_file.csv')

The program will look inside the folder product_graph_analysis.

I would like to set a path_file or base directory in the "mother_folder", the one that contains "csv" and "product_graph_analysis", in this way I could access all folders of my project from within database_functions.py

Upvotes: 0

Views: 2391

Answers (2)

The Dan
The Dan

Reputation: 1680

Well, I found a solution for this particular case that works fine:

import os
file='csv/my_file.csv'
BASE_DIR = os.path.dirname(os.path.abspath(__file__))
HOME_DIR = BASE_DIR.replace('/product_graph_analysis', '')
path_file = os.path.join(HOME_DIR, file)

Output:

>>> print(BASE_DIR)
'/home/mother_folder/product_graph_analysis'
>>> print(HOME_DIR)
'/home/mother_folder'

If yo know a 'better'/'more elegant' option let me know

Upvotes: 1

running.t
running.t

Reputation: 5709

So, you want to have BASE_DIR one directory up, right? Try this one

BASE_DIR = os.path.join(os.path.dirname(os.path.abspath(__file__)), '..')

Assuming this line is located in database_functions.py, with this statement you explicitly set BASE dir to the directory one level up (i.e. <directory of database_functions.py>/..) than the one in which database_functions.py is located specified by __file__ location.

Please note that this will affects all usages of BASE_DIR

Now whenever you want to open any file located in CSV subdirectory you should also set it appropriately e.g.

path_file = os.path.join(BASE_DIR, 'CSV', 'my_file.csv')

Upvotes: 0

Related Questions