Reputation: 127
anyone know how to insert this json array into mongodb using insertmany() and C# ??
i cant find any good source for this problem
Upvotes: 0
Views: 913
Reputation: 1179
MongoCollectionBase.InsertMany expects an IEnumerable<TDocument>
.
So you need to deserialize your data
json element to TDocument[], (Datum
) and then pass that array to InsertMany
.
Based on the below json, which is different from your screenshot
{
"data": [
{
"pulsa_code": "alfamart100",
"pulsa_op": "Alfamart Voucher",
"pulsa_nominal": "Voucher Alfamart Rp 100.000",
"pulsa_price": 100000,
"pulsa_type": "voucher",
"masaaktif": "0",
"status": "active"
}
]
}
This should work
//...
public class Datum
{
public string pulsa_code { get; set; }
public string pulsa_op { get; set; }
public string pulsa_nominal { get; set; }
public double pulsa_price { get; set; }
public string pulsa_type { get; set; }
public string masaaktif { get; set; }
public string status { get; set; }
public double harga { get; set; }
}
public class PriceListPrepaidModel
{
public List<Datum> data { get; set; }
}
public class PriceList : BaseDatabase
{
//NOTE: The strongly typed IMongoCollection<T> must be the same type as the entities passed to InsertMany
private IMongoCollection<Datum> _pricelistCollection;
//private IMongoCollection<PriceListPrepaidModel> _pricelistCollection;
public PriceList(IServiceProvider serviceProvider)
{
_pricelistCollection = DB.GetCollection<PriceListPrepaidModel>("price_prepaid");
}
public ResponseModel<string> PriceListPrepaidTest(PriceListPrepaidRequest request)
{
var entityResult = new ResponseModel<string>();
try
{
Console.WriteLine(response.Content);
//Desirialize to your model class, not JObject
var model = JsonConvert.DeserializeObject<PriceListPrepaidModel>(message.AsString);
foreach (var item in model.data)
{
item.pulsa_price = (int)item.pulsa_price + 200;
}
//Insert the array of `Datum`
_pricelistCollection.InsertMany(model.data);
entityResult.Value = JsonConvert.SerializeObject(model.data);
entityResult.Status = true;
}
catch (Exception ex)
{
entityResult.Messages.Add(new ResponseMessageModel()
{
Type = ResponseMessageModel.MessageType.ERROR,
Title = "Error",
Message = ex.Message
});
}
return entityResult;
}
}
Upvotes: 1