Reputation: 2123
I'm trying to get all users who are employers. So what I did was I filter the users where the id can be found in the "employer" field of any (other) user. However this gives me the following error:
TypeError: int() argument must be a string, a bytes-like object or a number, not 'builtin_function_or_method'
View:
# Get all employers
class Employers(viewsets.ModelViewSet):
queryset = CustomUser.objects.all()
serializer_class = CustomUserSerializer
def list(self, request):
#queryset = CustomUser.objects.all();
queryset = self.queryset.filter(id__in=CustomUser.objects.filter(employer=id)) #this gives me an error
serializer = CustomUserSerializer(queryset, many=True)
return Response(serializer.data)
Model (standard stuff):
# CustomUser model
class CustomUser(AbstractBaseUser):
username = None
email = models.EmailField(verbose_name='email address', max_length=255, unique=True)
date_joined = models.DateTimeField(verbose_name='date joined', auto_now_add=True)
last_login = models.DateTimeField(verbose_name='last login', auto_now=True)
is_admin = models.BooleanField(default=False)
is_active = models.BooleanField(default=True)
is_staff = models.BooleanField(default=False)
is_superuser = models.BooleanField(default=False)
employer = models.ForeignKey("self", blank=True, null=True, on_delete=models.DO_NOTHING)
USERNAME_FIELD = 'email'
REQUIRED_FIELDS = []
objects = MyUserManager()
def __str__(self):
return self.email
def has_perm(self, perm, obj=None):
return self.is_admin
def has_module_perms(selfself, app_label):
return True;
I'm not sure what I'm doing wrong. Any suggestions?
Upvotes: 1
Views: 136
Reputation: 477533
You can filter with an F
-expression [Django-doc] to refer to another column:
from django.db.models import F
class Employers(viewsets.ModelViewSet):
queryset = CustomUser.objects.all()
serializer_class = CustomUserSerializer
def get_queryset(self, *args, **kwargs):
return CustomUser.objects.filter(employer=F('pk'))
This thus makes a query that looks like;
SELECT customuser.*
FROM customuser
WHERE customuser.employer = customuser.id
or you can filter the relation in reverse to get CustomUser
s that employ at least one person:
class Employers(viewsets.ModelViewSet):
queryset = CustomUser.objects.all()
serializer_class = CustomUserSerializer
def get_queryset(self, *args, **kwargs):
return CustomUser.objects.filter(customuser__isnull=False).distinct()
This constructs a query that looks like:
SELECT DISTINCT customuser.*
FROM customuser
JOIN customuser u2 ON u2.employer = customuser.id
Upvotes: 1