Reputation: 139
I am following this tutorial :https://docs.snowflake.com/en/sql-reference/functions/validate.html
to try and 'return errors by query ID and saves the results to a table for future reference'
however for a seamless transfer I don't want to be putting the job id always as it would require me to go to snowflake console- go to history- get the jobid -copy and paste it to python code.
Instead I wanted to go with just the tablename which is a variable and 'last_query_id()' and give me the list errors. Is there any way i can achieve this?
import snowflake.connector
tableName='F58155'
ctx = snowflake.connector.connect(
user='*',
password='*',
account='*')
cs = ctx.cursor()
ctx.cursor().execute("USE DATABASE STORE_PROFILE_LANDING")
ctx.cursor().execute("USE SCHEMA PUBLIC")
try:
ctx.cursor().execute("PUT file:///temp/data/{tableName}/* @%
{tableName}".format(tableName=tableName))
except Exception:
pass
ctx.cursor().execute("truncate table {tableName}".format(tableName=tableName))
ctx.cursor().execute("COPY INTO {tableName} ON_ERROR = 'CONTINUE' ".format(tableName=tableName,
FIELD_OPTIONALLY_ENCLOSED_BY = '""', sometimes=',', ERROR_ON_COLUMN_COUNT_MISMATCH = 'TRUE'))
I have tried the below validate function....it is giving me error on this line
the error is "SQL compilation error: syntax error line 1 at position 74 unexpected 'tableName'. syntax error line 1 at position 83 unexpected '}'."
ctx.cursor().execute("create or replace table save_copy_errors as select * from
table(validate({tableName},'select last_query_id()'))");
ctx.close()
Upvotes: 0
Views: 1692
Reputation: 3465
The line
ctx.cursor().execute("create or replace table save_copy_errors as select * from
table(validate({tableName},'select last_query_id()'))");
should be replaced with these two
job_id = ctx.cursor().execute("select last_query_id()").fetchone()[0]
ctx.cursor().execute(f"create or replace table save_copy_errors as select * from
table(validate({tableName},job_id=>'{job_id}'))");
Upvotes: 1