Reputation: 9395
I have following collections in MongoDB
Profile Collection
> db.Profile.find()
{ "_id" : ObjectId("5ec62ccb8897af3841a46d46"), "u" : "Test User", "is_del": false }
Store Collection
> db.Store.find()
{ "_id" : ObjectId("5eaa939aa709c30ff4703ffd"), "id" : "5ec62ccb8897af3841a46d46", "a" : { "ci": "Test City", "st": "Test State" }, "ip" : false }, "op" : [ ], "b" : [ "normal" ], "is_del": false}
Item Collection
> db.Item.find()
{ "_id" : ObjectId("5ea98a25f1246b53a46b9e10"), "sid" : "5eaa939aa709c30ff4703ffd", "n" : "sample", "is_del": false}
Relation among these collections are defined as follows:
Profile -> Store
: It is 1:n
relation. id
field in Store
relates with _id
field in Profile
.Store
-> Item
: It is also 1:n
relation. sid
field in Item
relates with _id
field in Store
.Now, I need to write a query to find the all the store of profiles alongwith their count of Item
for each store. Document with is_del
as true
must be excluded.
I am trying it following way:
Then in the application logic use both the result to produce the combined output.
I have query 1 as follows:
db.Item.aggregate({$group: {_id: "$sid", count:{$sum:1}}})
Query 2 is as follows:
db.Profile.aggregate([{ "$addFields": { "pid": { "$toString": "$_id" }}}, { "$lookup": {"from": "Store","localField": "pid","foreignField": "id", "as": "stores"}}])
In the query, is_del
is also missing. Is there any simpler way to perform all these in a single query? If so, what will be scalability impact?
Upvotes: 1
Views: 62
Reputation: 5245
You can use uncorrelated sub-queries, available from MongoDB v3.6
db.Profile.aggregate([
{
$match: { is_del: false }
},
{
$lookup: {
from: "Store",
as: "stores",
let: {
pid: { $toString: "$_id" }
},
pipeline: [
{
$match: {
is_del: false,
$expr: { $eq: ["$$pid", "$id"] }
}
},
{
$lookup: {
from: "Item",
as: "items",
let: {
sid: { $toString: "$_id" }
},
pipeline: [
{
$match: {
is_del: false,
$expr: { $eq: ["$$sid", "$sid"] }
}
},
{
$count: "count"
}
]
}
},
{
$unwind: "$items"
}
]
}
}
])
To improve performance, I suggest you store the reference ids as ObjectId
so you don't have to convert them in each step.
Upvotes: 2