Reputation: 39
In my c++ code, I would like to validate my user input to be an int between 1,10 using a do while loop. I am able to validated for integers outside of the range. However if user inputs a float or a letter, it becomes an infinite loop. My idea is to add a condition in my while loop for if the input is not an integer to keep asking for input. the CAPITAL letters is where I am having trouble.
#include <iostream>
using namespace std;
int main(){
cout << "Welcome, ";
int steps;
int count=0;
do{
cout << "How many? \n";
cin >> steps;
IF (STEPS IS NOT INTEGER==TRUE){
COUNT=1;
}
if (steps <1)
{
cout << "not enough...\n";
}
if (steps > 10){
cout << "too many steps.\n Please pick a lower number of steps.\n\n";
}
} while (steps < 1|| steps >10 || COUNT==1);
//doing stuff with valid input
return 0;
}
Essentially I am trying to add another condition that just returns a boolean. and if the boolean implies that the input is not valid, then it reassigns count to make sure the do while loops continues until the input is valid.
The problem i am working on asks for a max and min steps, since all of them were having a similar problem i tried to simplify it and forgot some of the edits.
Upvotes: 0
Views: 770
Reputation: 60208
You can check whether the input failed, i.e. the user entered something that could not be read as an int
like this:
if (cin.fail()) { // in place of IF (STEPS IS NOT INTEGER==TRUE)
cin.clear();
cin.ignore();
cout << "not an integer, try again\n";
continue;
}
This avoids the need for the COUNT
variable.
Also, your while
condition doesn't appear to match the checks inside the loop. What happens when step
is either 9
or 10
? You should be consistent with the checks inside the loop.
Upvotes: 2
Reputation: 1539
You could use the !
operator.
For example:
if ( !(std::cin >> steps) )
{
std::cin.clear();
std::cin.ignore();
std::cout << "Incorrect entry. Try again: ";
}
Also consider not using using namespace std;
.
Upvotes: 0