CODEWITHSUNDEEP
c++c++17
j__
j__

Reputation: 740

std::stoull but with string_view

Is there a std::stoull which takes a basic_string_view? I don't want to construct a string just to call std::stoull, especially since it takes it by const &.

If none exists, what is an efficient way to convert a std::basic_string_view to unsigned long long?

Upvotes: 2

Views: 2897

Answers (2)

Qaz
Qaz

Reputation: 61920

If you're looking for more efficiency, C++17 introduced lower-level conversions in <charconv> (live example):

#include <charconv>
#include <iostream>
#include <string_view>

using namespace std::literals;

int main() {
    const auto str = "2048"sv;

    unsigned long long result;
    auto [ptr, err] = std::from_chars(str.data(), str.data() + str.size(), result);

    if (err == std::errc{} && ptr == str.data() + str.size()) {
        std::cout << "Entire conversion successful: " << result;
    }
}

The reason I don't use str.begin() and str.end() is because the API works directly on const char*, not iterators.

Upvotes: 7

catnip
catnip

Reputation: 25388

No there isn't, and cppreference explains why:

stoull ... calls std::strtoull(str.c_str(), &ptr, base)

which requires a nul-terminated string (which std::string_view does not promise to provide).

Note, however, that std::string has a converting constructor that takes a string_view so you can write:

auto ull = std::stoull (std::string (my_string_view));

which is probably as good a solution as any.

Upvotes: 1

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