CODEWITHSUNDEEP
java
user13473569
user13473569

Reputation:

Need to find position of maximum of three numbers

I am trying to find the position of the maximum of three numbers that the user inputs. I do not know how to find the position of this but I can find max of the numbers.

Here is the task: Here is the method named getNumberOfMaxParam that takes three integer numbers and returns the position of the first maximum in the order of the method parameters.

UPDATE: I am trying to compare the int a.b.c but I get This method must return a result of type int error Code:

import java.util.Scanner;
class App {
  
  
  public static int getNumberOfMaxParam(int a, int b, int c) {

    int firstMax = Math.max(a, b);

    int highMax = Math.max(firstMax, c);
    
    if (a == highMax) {
      System.out.println("1");
    
    } else if (b == highMax) {
      System.out.println("2");
    
    } else if (c == highMax) {
      System.out.println("3");
    
    } else {
      return highMax;
    }
}

public static void main(String[] args) {

    Scanner scanner = new Scanner(System.in);

    final int a = scanner.nextInt();
    final int b = scanner.nextInt();
    final int c = scanner.nextInt();

    System.out.print(getNumberOfMaxParam(a, b, c));
  }
}

Now how do I find the position?

Upvotes: 0

Views: 429

Answers (2)

Jason
Jason

Reputation: 5246

You can do this with the Stream api. You simply pass an array of values in the order you want. Then create an IntStream of the values and find the max. Then create an IntStream of the indices and find the first value in the array to see if it matches max, and return the index.

private static int getIndexOfMax(int... values) {
    int max = IntStream.of(values).max().orElseThrow(IllegalStateException::new);
        
    return IntStream.range(0, values.length)
            .filter(index -> values[index] == max)
            .findFirst().orElseThrow(IllegalStateException::new);
}

int index = getIndexOfMax(1, 2, 3);

assert index == 2;

Upvotes: 1

Pharsa Thapa
Pharsa Thapa

Reputation: 326

**PS. It could be controversial if you supply same value for multiple inputs.** 



public static int getNumberOfMaxParam(int a, int b, int c) {
    
        int firstMax = Math.max(a, b);
    
        int highMax = Math.max(firstMax, c);
        return (highMax == a ? 1 : (highMax == b ? 2 : 3 );
      }

Upvotes: 0

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