CODEWITHSUNDEEP
c#random
Wolfy
Wolfy

Reputation: 4373

Get random double value which is most close to another double value (but still random)

Let say that I would like to get an random double value wich is:

  1. greater than -0.150
  2. less than +0.150
  3. most close to 0.440

This number must be random...

How can I do that?

Additional info:

Like you said... 0.440 is not in [-0.150, 0.150], but I need to generate an number close to that number in this range...

let say that I call:

getMyRandomNumber(-0.150, 0.150, 0.440)

I would like to get an number in the range [-0.150, 0.150] but that it isn't allways 0.150

I would like to get numbers like 0.139, 0.140, 0.121,...

If I call:

getMyRandomNumber(-0.150, 0.150, -0.440)

I would like to get numbers like -0.139, -0.140, -0.121,...

Upvotes: 0

Views: 442

Answers (2)

Andrei
Andrei

Reputation: 5005

Random's NextDouble() returns a random number between 0.0 and 1.0

If you want to get a random number in the interval (a, b) based on the random number from NextDouble() then you need to map the (0.0, 1.0) interval you get to the (a, b) interval you need.

The simplest way is to use this formula: result = a + (b - a) * X where X is the result from NextDouble()

If X is 0 then result will be a, if X is 1 then result will be b, for X between 0.0 and 1.0 the result will be between a and b.

If you want numbers close to a certain number (say 0.44) but no further than 0.15 away then you need to map the results into the (0.44 - 0.15, 0.44 + 0.15) interval.

Upvotes: 2

nirmus
nirmus

Reputation: 5103

Random g = new Random();
double max = double.MaxValue;
double a = g.NextDouble() * max - 0.150; // greater then -0.15
double b = -g.NextDouble() * max + 0.150; // less then 0.15

most close is not clearly definition

Upvotes: 0

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