CODEWITHSUNDEEP
awk
user3686069
user3686069

Reputation: 91

Second highest value based on fileds

I have the following text in a file , it is separated by delimiter(=) , I need to get second highest value for each group of second filed , I have tried below code and able to get the highest value , is there a way we can achieve using Unix command to get the expected output?

First highest Value :

cat File.txt | awk -F= '{if (a[$2] < $1 ) a[$2] = $1;}END{for(i in a )
{print i,a[i];}' OFS='='

Input :

20180526=AA   
20180530=BB
20180621=AA
20180630=BB
20180630=CC
20180630=DD
20180731=BB
20180731=CC
20180731=DD

Expected output:

20180526=AA
20180630=BB
20180630=CC
20180630=DD

Upvotes: 2

Views: 100

Answers (1)

tripleee
tripleee

Reputation: 189948

You'll need to keep two arrays, and demote to the second any value from the first which gets overwritten by a higher value. Then at the end print the second array instead.

awk -F= 'a[$2] < $1 { b[$2] = a[$2]; a[$2] = $1; }
    END{for (i in b) print i, b[i];}' OFS='=' file.txt

(Also notice how we avoid the useless cat.)

This doesn't attempt to do anything useful with values which only occur once; if you can specify a behavior for those, it should be easy enough to add. (Ask a new question if you need help with that.)

Upvotes: 4

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