Reputation: 61
I want to rename the 'source' to something else in the following dataframe
source A to B Diff B to C Diff
risk_qty 4.909391e+07 0.0000
risk_delta 4.900294e+07 962.5669
risk_mtm 0.000000e+00 0.0000
risk_gamma 0.000000e+00 0.0000
risk_rho 8.322120e+01 0.0000
When I print the column names & indices this is what I get
Indices : ['risk_qty', 'risk_delta', 'risk_mtm', 'risk_gamma']
Columns: ['A to B Diff', 'B to C Diff']
But my issue is it's neither a column name nor an index, is this even achievable?
EDIT: If it helps I created this dataframe after performing a grpupby sum on 'source' & then transposing the dataframe.
I tried Sayandip's solution & ended up with following
source A to B Diff B to C Diff
foo
risk_qty 4.909391e+07 0.0000
risk_delta 4.900294e+07 962.5669
risk_mtm 0.000000e+00 0.0000
risk_gamma 0.000000e+00 0.0000
risk_rho 8.322120e+01 0.0000
Upvotes: 2
Views: 779
Reputation: 15872
Use df.index.name
:
>>> df.index.name = 'foo'
>>> df
foo A to B Diff B to C Diff
risk_qty 4.909391e+07 0.0000
risk_delta 4.900294e+07 962.5669
risk_mtm 0.000000e+00 0.0000
risk_gamma 0.000000e+00 0.0000
risk_rho 8.322120e+01 0.0000
Same can be achieved using:
df.index.set_names('foo',inplace=True)
Ah, got your edit, try:
>>> df.columns.name = 'foo'
Upvotes: 4