CODEWITHSUNDEEP
c++
Jozese
Jozese

Reputation: 35

String to char array in c++

I was making a simple program in c++ to convert a string to a char array and then print it out. My code is:

string UserImput;
int lenght;

 
 void Test()
{
     getline(cin, UserImput);
     
     lenght = UserImput.size();

     char char_array[lenght + 1];
     copy(UserImput.begin(), UserImput.end(), char_array);

    
     cout << char_array;
   
}

The error I am getting is "expression must have a costant value" and I do not know why.

Upvotes: 1

Views: 265

Answers (2)

Andy
Andy

Reputation: 13547

In char char_array[lenght + 1];, lenght + 1 is not a compile-time constant. The size of an array must be known at compile-time. Since the value of length is not known until runtime, you will need to allocate memory dynamically in this situation. For example:

char* char_array = new char[lenght + 1];

Don't forget to delete the array when you are done:

delete[] char_array;

Upvotes: 5

Vlad Feinstein
Vlad Feinstein

Reputation: 11311

You can use:

  char* c = _strdup(UserImput.c_str());

But I wonder - why? Just to output it to cout? Then you can do:

cout << UserImput.c_str();

Upvotes: 0

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