CODEWITHSUNDEEP
c++
Meekaa Saangoo
Meekaa Saangoo

Reputation: 349

Why does this code give the error "cannot bind non-const lvalue reference of type ‘char*&’ to an rvalue of type ‘char*’"

Why does the following code give this error:

cannot bind non-const lvalue reference of type char*& to an rvalue of type char*

#include <string>

int main()
{
    std::string p {"Test string"};
    auto &r = p.data();
    return 0;
}

The type of the pointer returned by std::string::data is char *. And the type of variable r is char *&. So why, in this case, the type of char * cannot be referenced by a type of char *?

Upvotes: 5

Views: 19723

Answers (1)

Kaldrr
Kaldrr

Reputation: 2850

The reason is that the C++ standard doesn't allow non-const references to bind to temporaries, and std::string::data returns a pointer by value. Only const reference can do that, and prolong the life of the temporary object.

In your case you either need to make your reference const.

const auto& r = p.data();

Or better, just create a variable that will store the pointer for you, as pointers are cheap to copy around.

const char* r = p.data();

Upvotes: 8

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